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2 years ago

11

You have been asked to create a poster to advertise the spring fling. You have a 3 inch by 5 inch postcard that you want to enla

rge. You want the enlargement to be 45 inches long. How wide will it be?

1 answer:

Kaylis [27]2 years ago

7 0

3/5 *45/A is the equation
therefore A would equal 5*15
which is then be 75 inches

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Elina [12.6K]

Answer: Margin of error = 6.58

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Step-by-step explanation:

Since we have given that

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At 95% confidence interval,

α = 0.05

t = 1.96

So, Margin of error is given by

$t\times \dfrac{\sigma}{\sqrt{n}}\\\\=1.96\times \dfrac{9.5}{\sqrt{8}}\\\\=6.58$

Confidence interval would be

Lower limit:

$\bar{x}-6.58\\\\=33.5-6.58\\\\=26.91$

Upper limit:

$\bar{x}+6.58\\\\=33.5+6.58\\\\=40.08$

Hence, the interval would be (26.91, 40.08)

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Confidence interval using the standard normal distribution is wider than the confidence interval using t distribution.

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