Question

The original price P for a necklace is the same at both jewelry stores. At Store A, the sale price is 60% of the original price. Last month, at Store B, the sale rice was $40 less than the original price. This month, Store B is selling the necklace for 80% of last months reduced price. The current sale prices are the same for both stores. Write and solve an equation to find the original price of the necklace.

Answer 1

Let the original price of the necklace be 'x'
Store A's price = 60% of x = 0.6x

Store B's price (last month) = x - 40
Store B's price (this month) = 80% of (x - 40) = 0.8(x - 40)

Store A's price = Store B's price
0.6x = 0.8(x - 40)
0.6x = 0.8x - 32
32 = 0.8x - 0.6x
32 = 0.2x
x = 32÷0.2
x = 160

Original price of the necklace is $160