Answer: 8.47
Step-by-step explanation:
Hope this helps!
There is a reflection along the y-axis
so the AB = SG = AB you may put it if they ask or not
BC = GP
CA = PS
Are you sure that both a and b are zero?
I doubt it.
<span>-8a^8b^-2/10a^-4b^-10
should surely be written as a fraction for clarity:
</span><span>-8a^8b^-2
----------------- (at least this is how I interpret your question)
10a^-4b^-10
-8a^8 divided by 10a^(-4) comes out to (-8/10)a^12, and
b^(-2) divided by b^(-10) comes out to b^8
so that your final quotient is (-4/5)(a^12)(b^8).</span>
The area of sector is calculated by the product of area of the circle and the sector angle. It is expressed as follows:
Area = πr² (α/360)
Area = π(8)²(45/360)
Area = 8π in²
Hope this answers the question. Have a nice day. Feel free to ask more questions.
I think it is 3 but just to make sure check other answerssorry