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Stels [109]
4 years ago
11

-2 (m+n-4)+5 (-2m+2n)+n (m+4n-5)

Mathematics
1 answer:
Natalka [10]4 years ago
5 0
So if you want to add
we distribute
a(b+c)=ab+ac so
-2(m+n-4)=-2m-2n+8

5(-2m+2n)=-10m+10n

n(m+4n-5)=mn+4n^2-5n

so total we ahve
-2m-2n+8-10m+10n+mn+4n^2-5n
group like terms
4n^2+-2m-10m-2n+10n-5n+mn+8
add like temrs
4n^2-12m+3n+mn+8
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<span>-8a^8b^-2/10a^-4b^-10
should surely be written as a fraction for clarity:

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-----------------          (at least this is how I interpret your question)
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so that your final quotient is (-4/5)(a^12)(b^8).</span>
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