Please help me with these questions

Kara is using a collection of old buttons for a craft project.She sorts the buttons by their sizes.The line plot shows the resul

MariettaO [177]

.25*3=.75
.375*2=.75
.5*2=2.0
.625*2=1.25
.75*3=2.25
.875*2=1.75
1*2=2
1.25*2=2.5
1.5*2=3
1.5+2=3.5
1.25+2.25=3.5+3.5=7
3.5+1.75=5.25
5.25+4.5=9.75
9.75+3=12.75

answer = 12.75in^2

7 0

3 years ago

Read 2 more answers

About how many pounds of coffee will you need to make 600 medium cups of coffee?

Veronika [31]

Answer:

A. 10

Step-by-step explanation:

I found a website that explains that you need 8.3 grams of coffee to make one 5-fl oz cup of coffee.

To make 600 cups, you need 600 * 8.3 g = 4980 g

Now we convert 4980 g to lb.

1 lb = 454 g

4980 g * (1 lb)/(454 g) = 11 lb

The closest answer is A. 10

Answer: A. 10

6 0

3 years ago

Estimate the length of one side of a square floor, if the area is 320 square feet. Give the whole number that is closest to the

RSB [31]

Let us assume the length of a side of the square floor = x feet
Area of the square floor as given in the question = 320 square feet
Then
x^2 = 320
x^2 = (17.89)^2
Then
x = 17.89
= 18 feet approx

From the above deduction, it can be easily concluded that the correct option among all the options that are given in the question is the second option or option "B".

3 0

3 years ago

In a survey, the planning value for the population proportion is . How large a sample should be taken to provide a confidence in

tatuchka [14]

Answer:

n=350

Step-by-step explanation:

Notation and definitions

$n$ random sample taken (variable of interest)

$\hat p=0.35$ estimated proportion (value assumed)

$p$ true population proportion

Confidence =0.95 or 95% (value assumed)

Me=0.05 (value assumed)

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})$

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by $\alpha=1-0.95=0.05$ and $\alpha/2 =0.025$ . And the critical value would be given by: