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2 years ago

Two thirds plus two fourths equals what

Mathematics

2 answers:

Nikitich [7]2 years ago

7 0

1 1/6, because if you at them you get 14/2 but that is improper so you make it into 1 1/6

garri49 [273]2 years ago

7 0

2/3 + 2/4
Find a common denominator whatever you do to the denominator you do to the numerator.
2 x 4 and 3 x 4 = 8/12
2 x 3 and 4 x 3 = 6/12
Add 8 and 6
8+6=14 14/12
Now because it is an improper fraction ask how many times 12 goes into 14.
1
Then the remainder is your numerator and the denominator stays the same.
1 2/12
Now we need to find the lowest common multiple. They can both be divided by 2.
2÷2=1 12÷2=6
They can't be divided anymore so the answer is:
1 1/6

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olga nikolaevna [1]

Answer:

Those little "sticks" are called absolute value.

For example, the absolute value of 2 is 2, and the absolute value of −2 is also 2. The absolute value of a number may be thought of as its distance from zero along real number line.

Thus, it doesn't matter if the number is positive or negative. As it only counts its distance from 0, on the number line.

I hope it helps.

5 0

1 year ago

Read 2 more answers

(3v^4 - 2) - (7v^4 + 6)

Lera25 [3.4K]

So firstly, you want to foil - (7v^4 + 6) [Think of the minus sign as -1]: $3v^4 - 2 - 7v^4 - 6$

Next, combine like terms and your answer will be: $-4v^4-8$

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2 years ago

Jessica Barth 15 pieces of ribbon each piece of ribbon was 2.25 yards long what is the total amount of ribbon Jessica bu Jessica

Flauer [41]

The answer is 3.375

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2 years ago

Evaluate the integral. 3 2 t3i t t − 2 j t sin(πt)k dt

sveta [45]

∫(t = 2 to 3) t^3 dt

= (1/4)t^4 {for t = 2 to 3}

= 65/4.

----

∫(t = 2 to 3) t √(t - 2) dt

= ∫(u = 0 to 1) (u + 2) √u du, letting u = t - 2

= ∫(u = 0 to 1) (u^(3/2) + 2u^(1/2)) du

= [(2/5) u^(5/2) + (4/3) u^(3/2)] {for u = 0 to 1}

= 26/15.

----

For the k-entry, use integration by parts with

u = t, dv = sin(πt) dt

du = 1 dt, v = (-1/π) cos(πt).

So, ∫(t = 2 to 3) t sin(πt) dt

= (-1/π) t cos(πt) {for t = 2 to 3} - ∫(t = 2 to 3) (-1/π) cos(πt) dt

= (-1/π) (3 * -1 - 2 * 1) + [(1/π^2) sin(πt) {for t = 2 to 3}]

= 5/π + 0

= 5/π.

Therefore,

∫(t = 2 to 3) <t^3, t√(t - 2), t sin(πt)> dt = <65/4, 26/15, 5/π>.

3 0

2 years ago

Write the following ratio using two other notations 8/9 Notation one Notation two

inessss [21]

I believe notation one would be 8:9 and notation two would be 8 to 9

5 0

2 years ago