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sukhopar [10]
3 years ago
14

y^{2} -z^{2}+6xy-6x+4z" alt="-3x^{2} -4y^{2} -z^{2}+6xy-6x+4z" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
vovikov84 [41]3 years ago
8 0
What are the directions??
You might be interested in
Please help
bezimeni [28]

Answer:

26-4s=9s

26-(4s-9s)=0

26+5s=0

5s=-26

ans: s= -26/5

-3r+10=15r-8

-3r-15r=-8-10

-18r=-18

18r=18

ans: r=1

-9(t-2)=4(t-15)

-9t+18=4t-60

-9t-4t=-60-18

-13t=-78

13t=78

ans: t=26

THERE U GO! :D

5 0
2 years ago
Read 2 more answers
Please help me I'm desperate!
Alexus [3.1K]
R = ((3V)/((pi)(h^2))+h)/3
6 0
3 years ago
-1/225x^2+2/3x what is the vertex of this quadratic function?
Julli [10]
\bf \textit{vertex of a parabola}\\ \quad \\\\

\begin{array}{lccclll}
y=&-\frac{1}{225}x^2&+\frac{2}{3}x\\\\
y=&-\frac{1}{225}x^2&+\frac{2}{3}x&+0\\
&\uparrow &\uparrow &\uparrow \\
&a&b&c
\end{array}\qquad 
\left(-\cfrac{{{ b}}}{2{{ a}}}\quad ,\quad  {{ c}}-\cfrac{{{ b}}^2}{4{{ a}}}\right)
6 0
3 years ago
Rearrange x = 3g + 2 to make g the subject​
lord [1]

Answer:

g=\frac{x}{3} -\frac{2}{3}

Step-by-step explanation:

You divide 3 from both sides leaving you with g=(x/3)-(2/3)

Please mark my answer as brainlyest.

7 0
3 years ago
Emmett gathered some data to compare the monthly cost of renting a one-bedroom apartment in Dallas and Austin. The data collecte
Goryan [66]

Answer:

The correct options are;

a) The city's data has the higher median monthly apartment cost of the two cities by $155

b) The city's data had the greater variability among monthly apartment costs because the standard deviation was $49.13 more than that of the other set of data

Step-by-step explanation:

The given data for the cost of renting a one-bedroom apartment in Dallas is presented as follows;

$994, $1,322, $1,075, $1,189, $1,172, $1,465, $1,215, $930, $1,090, $1,288

Which can be arranged in increasing order and analyzed to find the interquartile range, mean and standard deviation using Microsoft Excel as follows;

$930, $994, $1,075, $1,090, $1,172, $1,189, $1,215, $1,288, $1,322, and $ 1,465

The first quartile, Q₁ = $1,054.75

The third quartile, Q₃ = $1,296.5

The interquartile range = Q₃ - Q₁ = $241.75

The median = $1,180.5

The average monthly cost = $1,174

The standard deviation of the sample = $159.9597

The given data for the cost of renting a one-bedroom apartment in Austin is presented in increasing order using Microsoft Excel as follows;

$900, $950, $1,100, $1,250, $1,296, $1,375, $1,389, $1,400, $1,450, $1,495

The interquartile range, mean and standard deviation are found using Microsoft Excel as follows;

The first quartile, Q₁ = $1,062.5

The third quartile, Q₃ = $1,412.5

The interquartile range = Q₃ - Q₁ = $1,412.5 - $1,062.5 = $350

The median = $1,335.5

The average monthly cost = $1,260.5

The standard deviation of the sample = $209.0945

The difference in the median cost of the two cities is $1,335.5 - $1,180.5 = $155

Therefore, the Austin's city data has the higher median monthly apartment cost of the two cities by $155

b) The difference in the sample standard deviation of the two cities is $209.0945 - $159.9597 = $49.13476

Therefore, the Austin city data had the greater variability among monthly apartment costs because the standard deviation was $49.13 more than that of the other set of data.

7 0
3 years ago
Read 2 more answers
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