Hmmm the object, is at rest, when dropped, so it has a velocity of 0 ft/s
the only force acting on the object, is gravity, using feet will then be -32ft/s²,
was wondering myself on -32 or 32.. but anyhow... we'll settle for the negative value, since it seems to be just a bit of convention issues
so, we'll do the integral to get v(t) then

when will it reach the ground level? let's set s(t) = 0

part B) check the picture below
Hello
Answer:
The correct answer is B
Step-by-step explanation:
You just use the Distribuatd property to solve
You multiply 10 to all the varibles inside the parthense
Becasued y is equal to 7 you would do 10x7=70
then 10x8=80
and 70+80=150
and the answer says the primeter is 150 when y=7
Hope this helps
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The dimensions that would result to maximum area will be found as follows:
let the length be x, the width will be 32-x
thus the area will be given by:
P(x)=x(32-x)=32x-x²
At maximum area:
dP'(x)=0
from the expression:
P'(x)=32-2x=0
solving for x
32=2x
x=16 inches
thus the dimensions that will result in maximum are is length=16 inches and width=16 inches
Answer:
y = -3x + 8
Step-by-step explanation: