Answer:
The fair charges $5 for admission. Tom is going to the fair today. Therefore, Tom will spend $5 for admission to the fair today.
The radius of a circle is one-half the length of the diameter of a circle. The diameter of a circle is 10 ft. Therefore, the radius of the circle is 5 ft.
Step-by-step explanation:
Deductive reasoning or deduction, is one of the two basic types of logical inferences. A logical inference is a connection from a first statement to a second statement for which the rules of logic show that if the first statement is true, the second statement should be true. Basically one logical statement defines the base of the argument to reach the conclusion.
Here we can see that in first case:
The fair charges $5 for admission, so we know the fact that it charges $5 for the admission, now whoever goes to the fair will have to spend $5 to get in. Tom is going to the fair so Tom will spend$5 for admission to the fair. Therefore, this statement is deductive reasoning.
Case 2:
The radius of a circle is one-half the length of the diameter, this sentence is a fact. Now the diameter of a circle is 10ft so it is obvious that based on the previous sentence we will calculate the radius of the circle that is half of the diameter.
So only these two examples are based on deductive reasoning.
The values are x= 0 and y= -3.
Step-by-step explanation:
The given equations are,
6x-5y=15...........................(1)
x=y+3................................(2)
Step:1
Modify the equation (2) in (x+y=constant) format,
x-y=3................................(3)
Step:2
The equation (3) is multiplied by 5 (5×Eqn(3))
5x-5y=15........................(4)
Step:3
Subtract the equation (1) and (4)
6x-5y=15.......................(1)
5x-5y=15.......................(4)
( - ) (∵ Eqn(1)-Eqn(4))
(6x-5x)+(-5y+5y)=(15-15)
(x)+(0)=(0)
x=0
Step:4
Substitute the X=0 in the equation (2),
x=y+3............................(2)
(∵ x=0)
0=y=3
y=-3
Step:5
Check for solution substitute values of X and Y in equation (1),
6x-5y=15...........................(1)
(∵ x=0, y=-3)
(6×0)-(5×(-3))=15
15=15
Result:
The solution for equation 6x-5y=15 and x=y+3 are
x=0 and y=-3.
