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Vilka [71]
2 years ago
11

What is the first quartile, Q1, of the data represented by the box plot?

Mathematics
2 answers:
atroni [7]2 years ago
5 0
In this box plot 12.5 would be your answer
MrRa [10]2 years ago
3 0

Answer:

12.5

Step-by-step explanation:

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Find the value of the underlined 9 10,698
Dvinal [7]
90-------tenths place
5 0
3 years ago
Please help . I’ll mark you as brainliest if correct
il63 [147K]

Answer:

30 m

Step-by-step explanation:

51-21=30

<h2><em><u>PLEASE VOTE BRAINLIEST GIVE THANKS</u></em></h2>
3 0
3 years ago
While shopping for​ clothes, Daniel spent ​$42 less than 3 times what Curtis spent. Daniel spent ​$21. Write and solve an equati
ratelena [41]

Answer:

$21

Step-by-step explanation:

21+42=63

x=63:3

x=$21

5 0
3 years ago
The spinner below is spun, then a month of the year is randomly selected. Find the probability of P(unshaded, then a month that
lana [24]

Answer:

C)150

Step-by-step explanation:

P (blue)  fraction = 2/8   decimal=.25     percent=25%

P(purple) fraction=0/8   decimal=0         percent =0%

P(not green)  fraction=5/8     decimal=.625     percent= 62.5%

P(not brown) fraction=8/8     decimal=1   percent =100%

2)Refer to the table on air travel selected airports. Suppose a flight that arrived at El Centro is selected at random. What is the probability that the flight did not arrive on time? write your answer as a fraction, decimal and percent.    

80% on time so 20% are not on time

20/100 ÷ 20 =1/5

20%, .2, 1/5

3)The spinner has 8 sectors labeled with letters. Each sector of the spinner below is the same size, as shown.

If the arrow is spun 400 times , how many times  would it be  expected to land on a sector labeled B?

A)50                 C)150

B)100                D)250

PLEASE MARK ME AS BRAINLIEST

7 0
3 years ago
Suppose N has a geometric distribution with parameter p. Derive a closed-form expression for E(N | N &lt;= k), k = 1,2,... Check
vfiekz [6]

Answer:

P(X= k) = (1-p)^k-1.p

Step-by-step explanation:

Given that the number of trials is

N < = k, the geometric distribution gives the probability that there are k-1 trials that result in failure(F) before the success(S) at the kth trials.

Given p = success,

1 - p = failure

Hence the distribution is described as: Pr ( FFFF.....FS)

Pr(X= k) = (1-p)(1-p)(1-p)....(1-p)p

Pr((X=k) = (1 - p)^ (k-1) .p

Since N<=k

Pr (X =k) = p(1-p)^k-1, k= 1,2,...k

0, elsewhere

If the probability is defined for Y, the number of failure before a success

Pr (Y= k) = p(1-p)^y......k= 0,1,2,3

0, elsewhere.

Given p= 0.2, k= 3,

P(X= 3) =( 0.2) × (1 - 0.2)²

P(X=3) = 0.128

3 0
2 years ago
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