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Lubov Fominskaja [6]
2 years ago
6

What is the percent of decrease from 4 to 1

Mathematics
1 answer:
Iteru [2.4K]2 years ago
5 0

Answer:

75%

Step-by-step explanation:

It went down by 3 so,

4-1=3

4 * 75% or 0.75=3

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larisa86 [58]

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$1.95         hope this helped

Step-by-step explanation:

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If p is true and q is false, then p ∨ q is true. <br> A. True<br> B. False
Marysya12 [62]

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no its false because p v q can only be true if both are true

Step-by-step explanation:

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3 years ago
Please help. Attached as an image
Triss [41]

Distance formula ds = v(dx² + dy²) s = ? v(1 + (dy/dx)²) dx ......... s = the arc length y = 171 - x²/45

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4 0
1 year ago
143+ [(96 + 8) 5] – 42.
Tresset [83]

Answer:

621

Explanation:

143 + (96 + 8)(5) − 42

(96 + 8)(5)

= 520

143 + 520 - 42

= 663

663 - 42

= 621

7 0
3 years ago
The volume V of an ice cream cone is given by V = 2 3 πR3 + 1 3 πR2h where R is the common radius of the spherical cap and the c
Nuetrik [128]

Answer:

The change in volume is estimated to be 17.20 \rm{in^3}

Step-by-step explanation:

The linearization or linear approximation of a function f(x) is given by:

f(x_0+dx) \approx f(x_0) + df(x)|_{x_0} where df is the total differential of the function evaluated in the given point.

For the given function, the linearization is:

V(R_0+dR, h_0+dh) = V(R_0, h_0) + \frac{\partial V(R_0, h_0)}{\partial R}dR + \frac{\partial V(R_0, h_0)}{\partial h}dh

Taking R_0=1.5 inches and h=3 inches and evaluating the partial derivatives we obtain:

V(R_0+dR, h_0+dh) = V(R_0, h_0) + \frac{\partial V(R_0, h_0)}{\partial R}dR + \frac{\partial V(R_0, h_0)}{\partial h}dh\\V(R, h) = V(R_0, h_0) + (\frac{2 h \pi r}{3}  + 2 \pi r^2)dR + (\frac{\pi r^2}{3} )dh

substituting the values and taking dx=0.1 and dh=0.3 inches we have:

V(R_0+dR, h_0+dh) =V(R_0, h_0) + (\frac{2 h \pi r}{3}  + 2 \pi r^2)dR + (\frac{\pi r^2}{3} )dh\\V(1.5+0.1, 3+0.3) =V(1.5, 3) + (\frac{2 \cdot 3 \pi \cdot 1.5}{3}  + 2 \pi 1.5^2)\cdot 0.1 + (\frac{\pi 1.5^2}{3} )\cdot 0.3\\V(1.5+0.1, 3+0.3) = 17.2002\\\boxed{V(1.5+0.1, 3+0.3) \approx 17.20}

Therefore the change in volume is estimated to be 17.20 \rm{in^3}

4 0
3 years ago
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