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kap26 [50]
3 years ago
9

What is the answer????

Mathematics
1 answer:
dem82 [27]3 years ago
6 0
E I think I am not sure though.
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It appears that people who are mildly obese are less active than leaner people. One study looked at the average number of minute
hoa [83]

Answer:

Obese people

Lower = \mu - 2\sigma = 373- 2(67) = 239

Upper = \mu + 2\sigma = 373+ 2(67) = 507

Lean People

Lower = \mu - 2\sigma = 526- 2(107) = 312

Upper = \mu + 2\sigma = 526+ 2(107) = 740

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

The empirical rule, also referred to as the three-sigma rule or 68-95-99.7 rule, is a statistical rule which states that for a normal distribution, "almost all data falls within three standard deviations (denoted by σ) of the mean (denoted by µ). Broken down, the empirical rule shows that 68% falls within the first standard deviation (µ ± σ), 95% within the first two standard deviations (µ ± 2σ), and 99.7% within the first three standard deviations (µ ± 3σ)".

Solution to the problem

Obese people

Let X the random variable that represent the minutes of a population (obese people), and for this case we know the distribution for X is given by:

X \sim N(373,67)  

Where \mu=373 and \sigma=67

On this case we know that 95% of the data values are within two deviation from the mean using the 68-95-99.7 rule so then we can find the limits liek this:

Lower = \mu - 2\sigma = 373- 2(67) = 239

Upper = \mu + 2\sigma = 373+ 2(67) = 507

Lean People

Let X the random variable that represent the minutes of a population (lean people), and for this case we know the distribution for X is given by:

X \sim N(526,107)  

Where \mu=526 and \sigma=107

On this case we know that 95% of the data values are within two deviation from the mean using the 68-95-99.7 rule so then we can find the limits liek this:

Lower = \mu - 2\sigma = 526- 2(107) = 312

Upper = \mu + 2\sigma = 526+ 2(107) = 740

The interval for the lean people is significantly higher than the interval for the obese people.

5 0
3 years ago
Your parents gave you a gift card for your favorite coffee shop. The card was worth $50 when you got it. Each day, you buy a dri
Sever21 [200]

50=3x+b. you never specify the variable that replaces b

7 0
3 years ago
What is the HCF and LCM of 268 and 244​
Ray Of Light [21]

Answer:

HCF = 4

LCF = 16348

HOPE THIS HELPS :)

5 0
3 years ago
Simplify the expression 4 squaere root of 9
nlexa [21]

Answer:

12

Step-by-step explanation:

4 / sqrt {9}

4(3)

4 x 3

12

7 0
2 years ago
*will give brainlist**okay so u want to know how much diapers u will use for 3 years basically and then the details to help u ea
pochemuha

ok so divide 1500 by 250 to determine how many boxes you need to by in 1 year

so that equals 6 then you multiply that by $30 to find the total cost of all the diapers per year so the is $180 per year and then multiply that by 3 to find the cost of all 3 years

So the answer is you will spend $540 in total

8 0
3 years ago
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