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QveST [7]
4 years ago
12

How to multiply numbers with and exponet outside of the parenthesis ​

Mathematics
1 answer:
Lemur [1.5K]4 years ago
3 0

Answer:

You distribute the exponent to each term in the parenthesis

Step-by-step explanation:

ex:  (3x³y)² becomes

3²(x²)³y²    which simplifies to

9(x^6)y²

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Find the product of (3 x 109) and (2 x 109). Write the final answer in scientific notation.
chubhunter [2.5K]

The  product of (3 x 109) and (2 x 109) in scientific notation is 6*10^9

<h3>What is scientific notation?</h3>

scientific notation can be described as the expression in the form  a x 10^b where a is a number or decimal number a is greater than or equal to one.

(3 x 109) * (2 x 109) =6*10^9

Therefore, option D is correct.

Learn more about scientific notation at:

brainly.com/question/27862246

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5 0
2 years ago
K^2 ; k = 4<br> pls help
Lisa [10]
It would be 16 since when you replace the k for the 4 it is 4^2 and 4 multiplied by itself (squared)=16. Hope this helps!
3 0
3 years ago
Solve the equation log 4(x + 20) = 3
Aleks [24]
the answer would be x=-19.25
6 0
3 years ago
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What is sqrt23 approximated to the nearest tenth <br><br> 3.6<br> 4.6<br> 4.8<br> 11.5
Dmitrij [34]
5^2 = 25  so i would say its 4.8 Answer
3 0
4 years ago
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Let T:P3→P3 be the linear transformation such that T(â’2x2)=3x2+4x, T(0.5x+3)=â’3x2+3xâ’4, and T(2x2â’1)=â’3x+4. Find T(1), T(
balu736 [363]

It looks like we're told that

T(-2x^2)=3x^2+4x

T\left(\dfrac12x+3\right)=-3x^2+3x-4

T(2x^2-1)=-3x+4

We use the fact that T is linear to find T(1),T(x),T(x^2). First, we notice that

T(-2x^2)+T(2x^2-1)=T(-2x^2+2x^2-1)=T(-1)=-T(1)

We also have

T\left(\dfrac12x+3\right)=T\left(\dfrac12x\right)+T(3)=\dfrac12T(x)+3T(1)

T(2x^2-1)=T(2x^2)-T(1)=2T(x^2)-T(1)

So once we find T(1), we can determine T(x) and T(x^2). We have

T(1)=-\left(T(-2x^2)+T(2x^2-1)\right)\implies T(1)=-3x^2-x-4

and using this we find

T(x)=12x^2+12x+16

T(x^2)=-\dfrac32x^2-2x

Then

T(ax^2+bx+c)=T(ax^2)+T(bx)+T(c)=aT(x^2)+bT(x)+cT(1)

T(ax^2+bx+c)=-\dfrac32\left(a-8b+2c\right)x^2-(2a-12b+c)x+16b-4c

8 0
3 years ago
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