What is sqrt23 approximated to the nearest tenth 3.6 4.6 4.8 11.5

2 answers:

8 0

When you calculate $\sqrt{23}$ to its approximate value,, you get about 4.79583. Now in order to round this number out to the nearest tenth,, we must look at the first number behind the decimal. If this number is smaller than 5 then we round down,, but if it is 5 or larger then we must round up. If you look at the first number behind the decimal for this number you can see that it is larger than 5,, so we must round up. This makes the correct answer to your question 4.8,, which can also be referred to as option C.
Let me know if you have any further questions
:)

Dmitrij [34]2 years ago

3 0

5^2 = 25 so i would say its 4.8 Answer

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Trigonometry

quester [9]

Answer:

$\frac{9 + 2 \sqrt{3} }{3} \\$

Step-by-step explanation:

$\cosec(30) + \cosec(60) + \cosec(90) \\ \\ = 2 + \frac{2}{ \sqrt{3} } + 1 \\ \\ = \frac{2 \sqrt{3 } + 2}{ \sqrt{3} } + 1 \\ \\ = \frac{2 \sqrt{3} + 2 + \sqrt{3} }{ \sqrt{3} } \\ \\ = \frac{3 \sqrt{3} + 2}{ \sqrt{3} } \\ \\ = \frac{3 \sqrt{3} + 2}{ \sqrt{3} } \times \frac{ \sqrt{3} }{ \sqrt{3} } \\ \\ = \frac{9 + 2 \sqrt{3} }{3}$