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3 years ago

62 7h in a word phrase

Mathematics

1 answer:

Vikentia [17]3 years ago

6 0

Sixty-two hours and 7 minutes

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A company that manufacturers deep freezers has developed a new formula of refrigerant, the substance used to cause cooling in re

bonufazy [111]

Answer:

response variable- time required for water to turn to ice

control group- second freezer

explanatory variable- new formula

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

20 POINTS FOR HELP!!

uranmaximum [27]

Y=3x+30
because if you look she automatically makes $30, and her salary goes up every time cone by 3

5 0

3 years ago

Read 2 more answers

The result of which expression will best estimate the actual product

prisoha [69]

Answer:

The answer is,

$(-1) \times \frac {1}{2} \times (-1) \times (1)$

Step-by-step explanation:

The given product is,

$\frac {-4}{5} \times \frac{3}{5} \times \frac{-6}{7} \times \frac {5}{6}$

= $\frac {12}{35}$

$\simeq 0.3429$ ---------------------(1)

Now, the first product to compare is,

$(-1) \times \frac {1}{4} \times (-1) \times (-1)$

= - 0.25 ----------------------------(2)

The second product to compare is,

$(-1) \times \frac {1}{2} \times (-1) \times (1)$

= 0.5 ------------------------(3)

The 3rd product to compare is,

$\frac {-4}{2} \times \frac {3}{2} \times \frac{-2}{5} \times \frac {5}{2}$

= 3 ----------------------------(4)

The 4th product to compare is,

$\frac {-3}{4} \times \frac {-3}{4} \times \frac {-1}{5} \times \frac {1}{2}$

= $\frac {-9}{160}$

= 0.05625 -----------------(5)

Comparing all the values , we get (3) is closest to (1).

Hence, we get, the answer is,

$(-1) \times \frac {1}{2} \times (-1) \times (1)$

3 0

3 years ago

1. There are 51 families in Oakville who have

marishachu [46]

Answer: 17 families

Step-by-step explanation:

3 0

3 years ago

Find the exact value of the following limit: lim x approaches 0 e^6x... check photo above.

horrorfan [7]

Substituting x = 0 directly gives the indeterminate form 0/0, so you can use l'Hopital's rule (and you'll have to do that twice):

$\displaystyle\lim_{x\to0}\frac{e^{6x}-6x-1}{x^2}=\lim_{x\to0}\frac{6e^{6x}-6}{2x}=\lim_{x\to0}\frac{36e^{6x}}2$

The limand is continuous everywhere, so you can plug in x = 0 to get 36•1/2 = 18.

8 0

3 years ago