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andrey2020 [161]

4 years ago

15

Given polygon ABCD with coordinates A(-2,1),B(0,3),C(1,-4),D(-1,-1), if polygon ABCD is rotated 90 degree angle counterclockwise

about the origin,then the coordinates of point A’are

1 answer:

AVprozaik [17]4 years ago

4 0

I dont know sorry man

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Write an equation in slope-intercept form for the line that satisfies the following condition. slope 7, and passes through (5, 3

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Y = mx + b
slope(m) = 7
(5,30)...x = 5 and y = 30
now we sub and find b, the y int
30 = 7(5) + b
30 = 35 + b
30 - 35 = b
-5 = b

so ur equation is : y = 7x - 5 <==

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-1/2 divided by 1 3/4 as a fraction in simplest form

Helen [10]

$\Large\textsf{\textbf{Answer\;:}}}$

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$\Large\textsf{\textbf{Calculations\::}}$

$-\displaystyle\frac{1}{2} :1\frac{3}{4}$

First , convert the mixed number (the fraction we are dividing by in the given maths problem) into an improper fraction .

Multiply the whole part (1) times the denominator (4) and add the numerator . The result is the numerator of our fraction , and the denominator stays the same .

So now our maths problem looks as follows :

$-\displaystyle\frac{1}{2} :\frac{7}{4}$

Now turn the fraction you are dividing by over :

$-\displaystyle\frac{1}{2} *\frac{4}{7}$

Now multiply the numerator of the first fraction times the numerator of the second fraction :

4

Perform the same operation with the denominators :

-4/14

So the result is :

$-\displaystyle\frac{4}{14}$

Since the above fraction is not in it's simplest form , we divide the top and bottom by 2 (a common factor of both 4 and 14) :

$-\displaystyle\frac{2}{7}$

$\footnotesize\textsf{hope\:helpful~}$

8 0

3 years ago