Answer:
Step-by-step explanation: This is the quadratic function:
h(x)=ax²+bx+c
We have two points:
(1,58)
(2,112)
Now, we calculate this quadratic funtion.
we assume that h(0)=0
Therefore:
a(0)²+b(0)+c=0
c=0
(1,58)
a(1)²+b(1)=58
a+b=58 (1)
(2,112)
a(2)²+b(2)=112
4a+2b=112
2a+b=56 (1)
With the equations (1) and (2) we make a system of equations:
a+b=58
2a+b=56
we can solve this system of equations by reduction method.
-(a+b=58)
2a+b=56
---------------------
a=-2
-2(a+b=58)
2a+b=56
-------------------
-b=-60 ⇒ b=60
The function is:
h(x)=ax²+bx+c
h(x)=-2x²+60x
Now find the height, in feet, of the rock after 10 seconds in the air.
h(10)=-2(10)²+60(10)
h(10)=-200+600=400
Answer: 400 ft.
Answer:
isk
Step-by-step explanation:
27 / 3 =9
54 / 6 = 9
so 18 / 9 = 2
Answer: Missing side length AB = 2
We know the y intercept is 16 because y=16 when x=0.
Find slope by calculating change in y over change in x.
(12-16)/(2-0)
-4/2
-2
Plug both values into slope intercept form. y=mx+b where m is slope and b is the y intercept.
Final answer: y=-2x+16
Answer:
6'8
Step-by-step explanation:
