Answer:
−20x − 8
Step-by-step explanation:
37 because you add 13+10=23 7+7=14 and 23+14=37
Answer:
Answer choice a is correct, the answer would be 4.
Step-by-step explanation:
The histogram shows that the bin from 1-3 has a height of 4 shots, and all of the bins to the right include values of ≥4.
The question asks for the number of games that had less than 4 shots, which means that and number of shots greater than or equal to 4 would not be counted. Thus, only the first bin is included in the answer.
Answer:
Given sides 12, 16 and 20 can be the sides of right triangle.
Step-by-step explanation:
Sides of right triangle always follow the Pythagoras theorem.
i.e 
For the given Lengths 7, 40 and 41
We need to check if


That means, 
hence 7,40 and 41 can not be the sides of right triangle.
Next,
Given sides 12,16 and 20.
Again follow the similar process used in the above problem.

Therefore given sides 12,16 and 20 can be the sides of right triangle.