All categories

3 years ago

Irrational equations 64^1/3 how to simplify?

Mathematics

2 answers:

balandron [24]3 years ago

6 0

For indicies, the numerator is the normal power, and the denominator is a root as such. So 1/2 would be square root, 1/3 would be cube root, 1/4 would be 4th root and so on.

So, 64^(1/3) is the third root of 64, which is equal to 4.

Igoryamba3 years ago

3 0

My answer on pitcure :)

You might be interested in

Cuanto me da como resultado

Likurg_2 [28]

Step-by-step explanation:

1) $(-4)^2{\cdot}(-4)$

We know that, $a^x{\cdot}a^y=a^{x+y}$

$(-4)^2{\cdot}(-4)=(-4)^{2+1}\\\\=(-4)^3\\\\=64$

2) $(-2)^5{\cdot} (-2)^3$

Again using above property,

$(-2)^5{\cdot} (-2)^3=(-2)^8\\\\=256$

3) $5^{-3}$

We know that,

$a^{-x}=\dfrac{1}{a^x}$

So,

$5^{-3}=\dfrac{1}{5^3}\\\\=\dfrac{1}{125}$

4) $2.5^2=2.5\times 2.5\\\\=6.25$

Hence, this is the required solution.

4 0

2 years ago

Solve the system of equations

34kurt

Answer:

y=17/2 and x=15/8

Step-by-step explanation:

By subsitution, we get 4x+4x+1=16, so 8x=15. Thus, x=15/8. Next, we plug x in to find y. y=4*15/8 +1, or 15/2 +1 = 17/2

5 0

2 years ago

Read 2 more answers

60731903239__8DEE49CD-5BBC-40E2-A8F5-59B32FE3879C.jpeg

Sergio [31]

Answer:No

Step-by-step explanation:

4 0

3 years ago

Suppose you and some friends go to the movies and buy some snacks. The snack bar charges $2 for a box of candy and $6 for the “c

aleksley [76]

If what you are trying to do is buy the most you can and still having some change left over then the answer would be 1 combo and 2 boxes of candy

3 0

2 years ago

fred is playing tennis fo every 2 of his serves that land in 4 serves land out if he hit 26 serves in how many serves landed out

ki77a [65]

Answer:

52 serves landed out

Explanation:

If you divide the number of serves in by 2 ( number that he lands in for every 6 serves) and then multiply by 4 ( number that land out for every 6 serves), you get 52 serves out.

3 0

3 years ago