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ludmilkaskok [199]
3 years ago
8

hey, do any of you guys know how to plot functions on a graph. You know like f(X) and g(X)? I find it really hard and also do yo

u have any tips?
Mathematics
1 answer:
Tpy6a [65]3 years ago
3 0
It helps if you have an example, like f(x) = 2x+3
What you typically do, is:

- draw xy axis, label them (ie., 1,2,3,4 along both axes)
- calculate the f(x) values for several x (e.g., -2, 0, 1, 3, doesn't matter).
- plot the calculated values as points. The calculated f(x) is your y value.
- sketch a smooth line through the points. It helps if you know in advance if the line is going to be straight or curved. 
- The more points you calculate, the more accurate your graph will be
You might be interested in
The sum of three consecutive even integers is 258. write an equation ad solve to find the integers
slavikrds [6]

The consecutive integers are 85,86,87

Explanation:

n

:

the first number

n

+

1

:

the second number

n

+

2

:

the third number

n

+

(

n

+

1

)

+

(

n

+

2

)

=

258

3

n

+

3

=

258

3

n

=

258

−

3

3

n

=

255

n

=

255

3

n

=

85

n

+

1

=

85

+

1

=

86

n

+

2

=

85

+

2

=

87

8 0
3 years ago
Read 2 more answers
The taxi and takeoff time for commercial jets is a random variable x with a mean of 8.3 minutes and a standard deviation of 3.3
In-s [12.5K]

Answer:

a) There is a 74.22% probability that for 37 jets on a given runway, total taxi and takeoff time will be less than 320 minutes.

b) There is a 1-0.0548 = 0.9452 = 94.52% probability that for 37 jets on a given runway, total taxi and takeoff time will be more than 275 minutes.

c) There is a 68.74% probability that for 37 jets on a given runway, total taxi and takeoff time will be between 275 and 320 minutes.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}.

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

The taxi and takeoff time for commercial jets is a random variable x with a mean of 8.3 minutes and a standard deviation of 3.3 minutes. This means that \mu = 8.3, \sigma = 3.3.

(a) What is the probability that for 37 jets on a given runway, total taxi and takeoff time will be less than 320 minutes?

We are working with a sample mean of 37 jets. So we have that:

s = \frac{3.3}{\sqrt{37}} = 0.5425

Total time of 320 minutes for 37 jets, so

X = \frac{320}{37} = 8.65

This probability is the pvalue of Z when X = 8.65. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{8.65 - 8.3}{0.5425}

Z = 0.65

Z = 0.65 has a pvalue of 0.7422. This means that there is a 74.22% probability that for 37 jets on a given runway, total taxi and takeoff time will be less than 320 minutes.

(b) What is the probability that for 37 jets on a given runway, total taxi and takeoff time will be more than 275 minutes?

Total time of 275 minutes for 37 jets, so

X = \frac{275}{37} = 7.43

This probability is subtracted by the pvalue of Z when X = 7.43

Z = \frac{X - \mu}{\sigma}

Z = \frac{7.43 - 8.3}{0.5425}

Z = -1.60

Z = -1.60 has a pvalue of 0.0548.

There is a 1-0.0548 = 0.9452 = 94.52% probability that for 37 jets on a given runway, total taxi and takeoff time will be more than 275 minutes.

(c) What is the probability that for 37 jets on a given runway, total taxi and takeoff time will be between 275 and 320 minutes?

Total time of 320 minutes for 37 jets, so

X = \frac{320}{37} = 8.65

Total time of 275 minutes for 37 jets, so

X = \frac{275}{37} = 7.43

This probability is the pvalue of Z when X = 8.65 subtracted by the pvalue of Z when X = 7.43.

So:

From a), we have that for X = 8.65, we have Z = 0.65, that has a pvalue of 0.7422.

From b), we have that for X = 7.43, we have Z = -1.60, that has a pvalue of 0.0548.

So there is a 0.7422 - 0.0548 = 0.6874 = 68.74% probability that for 37 jets on a given runway, total taxi and takeoff time will be between 275 and 320 minutes.

7 0
3 years ago
Find the slope of the line that passes through (6, 7) and (2, 10). and simplify if needed thx guys.
tekilochka [14]

Answer:

-\frac{3}{4}

Step-by-step explanation:

the equation for finding the slope of a line when given two points is \frac{y_2-y_1}{x_2-x_1}, aka the change in y over the change in x.

pick one of your coordinate pairs to be y_2\\ and x_2. it doesn't matter which coordinate pair you choose as long as you keep them as y_2\\ and x_2. the remaining coordinate pair will be y_1 and x_1.

for this example, i'll use (2, 10) for y_2\\ and x_2 and (6, 7) for y_1 and x_1.

<em>**before i begin, i just want to note that you can do these next four steps in any order that you want. i personally prefer to plug in my y-values first and then my x-values, but you can choose to instead plug in the values of each coordinate pair (like starting by plugging in the coordinate pair (2, 10) with 10 for </em>y_2\\ and 2 for x_2<em>). it's up to you. i'm going to explain the steps by plugging in my y-values first and then my x-values because that's the way i normally do it.</em>

<em />

first, start by plugging in the y-value from the coordinate pair of your choosing in for y_2\\. since i chose (2, 10) for y_2\\ and x_2, i'll plug in 10 for y_2\\.

\frac{y_2-y_1}{x_2-x_1} ⇒ \frac{10-y_1}{x_2-x_1}

then plug in the remaining coordinate pair's y-value in for y_1. since the coordinate pair that's left is (6, 7), i will plug in 7 for y_1.

\frac{y_2-y_1}{x_2-x_1} ⇒ \frac{10-7}{x_2-x_1}

now i'm going to plug in the x-values. i chose (2, 10) to plug in for y_2\\ and x_2, so now i'll plug in 2 for x_2.

\frac{y_2-y_1}{x_2-x_1} ⇒ \frac{10-7}{2-x_1}

and all that's left to plug in is the x-value from (6, 7), so i will plug that in for x_1.

\frac{y_2-y_1}{x_2-x_1} ⇒ \frac{10-7}{2-6}

after plugging in all the values, you have \frac{10-7}{2-6}.

subtract 10 - 7 as well as 2 - 6.

\frac{10-7}{2-6} ⇒ \frac{3}{-4}

\frac{3}{-4} cannot be simplified, therefore the slope of the line is \frac{3}{-4} or -\frac{3}{4}.

i hope this helps! have a lovely day <3

7 0
3 years ago
Convert 11/8 and 5/9 to decimals
svetlana [45]

Answer:

Step-by-step explanation:

11/8 as a decimal... 1.375

5/9 as a decimal... 0.55555556

8 0
3 years ago
Read 2 more answers
2 more than 7 times Lynn age
iVinArrow [24]
Lynn age: 7x+2. That's if you wanted an equation.
8 0
3 years ago
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