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ludmilkaskok [199]
3 years ago
8

hey, do any of you guys know how to plot functions on a graph. You know like f(X) and g(X)? I find it really hard and also do yo

u have any tips?
Mathematics
1 answer:
Tpy6a [65]3 years ago
3 0
It helps if you have an example, like f(x) = 2x+3
What you typically do, is:

- draw xy axis, label them (ie., 1,2,3,4 along both axes)
- calculate the f(x) values for several x (e.g., -2, 0, 1, 3, doesn't matter).
- plot the calculated values as points. The calculated f(x) is your y value.
- sketch a smooth line through the points. It helps if you know in advance if the line is going to be straight or curved. 
- The more points you calculate, the more accurate your graph will be
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4 0
3 years ago
find the smallest number of terms of the AP "-54,-52.5,-51,-49.5" ....that must be taken for the sum of the terms to be positive
wel

The smallest number of terms of the AP that will make the sum of terms positive is 73.

Since we need to know the number for the sum of terms, we find the sum of terms of the AP

<h3>Sum of terms of an AP</h3>

The sum of terms of an AP is given by S = n/2[2a + (n - 1)d] where

  • n = number of terms,
  • a = first term and
  • d = common difference

Since we have the AP "-54,-52.5,-51,-49.5" ....", the first term, a = -54 and the second term, a₂ = -52.5.

The common difference, d = a₂ - a

= -52.5 - (-54)

= -52.5 + 54

= 1.5

<h3>Number of terms for the Sum of terms to be positive</h3>

Since we require the sum of terms , S to be positive for a given number of terms, n.

So, S ≥ 0

n/2[2a + (n - 1)d] ≥ 0

So, substituting the values of the variables into the equation, we have

n/2[2(-54) + (n - 1) × 1.5] ≥ 0

n/2[-108 + 1.5n - 1.5] ≥ 0

n/2[1.5n - 109.5] ≥ 0

n[1.5n - 109.5] ≥ 0

So, n ≥ 0 or 1.5n - 109.5 ≥ 0

n ≥ 0 or 1.5n ≥ 109.5

n ≥ 0 or n ≥ 109.5/1.5

n ≥ 0 or n ≥ 73

Since n > 0, the minimum value of n is 73.

So, the smallest number of terms of the AP that will make the sum of terms positive is 73.

Learn more about sum of terms of an AP here:

brainly.com/question/24579279

#SPJ1

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