Answer:
A 90% confidence interval for the mean number of letter sounds identified in one minute is: (30.84, 37.34).
Step-by-step explanation:
We have that to find our 
level, that is the subtraction of 1 by the confidence interval divided by 2. So:
Now, we have to find z in the Ztable as such z has a pvalue of 
.
That is z with a pvalue of 
, so Z = 1.645.
Now, find the margin of error M as such
In which 
is the standard deviation of the population and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 34.09 - 3.25 = 30.84.
The upper end of the interval is the sample mean added to M. So it is 34.09 + 3.25 = 37.34.
A 90% confidence interval for the mean number of letter sounds identified in one minute is: (30.84, 37.34).
Answer:
D) 4
Step-by-step explanation:
Answer:
3+3+3x
i think idk just getting points goog luck
Step-by-step explanation:
The first step for solving this question is put both of your given expressions into one and then subtract them. This will look like the following:
8 ×
- 2 × 10²]
Now to make the calculation easier,, factor the expression.
(8 ×
- 2) × 10²
Evaluate the power inside the parenthesis.
(8 × 10000 - 2) × 10²
Evaluate the power outside the parenthesis.
(8 × 10000 - 2) × 100
Multiply the numbers inside the parenthesis.
(80000 - 2) × 100
Subtract the numbers in the parenthesis.
79998 × 100
Lastly,, multiply the numbers together to get your final answer.
7999800
This means that 8 ×
is 7999800 times larger than 2 × 10².
Let me know if you have any further questions.
:)
1. D
2. E
3. B
4. Pentagon
5. C
