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3 years ago

15

Write the range of

la1" title="y = (x - 2 ){}^{2} + 4" alt="y = (x - 2 ){}^{2} + 4" align="absmiddle" class="latex-formula">

1 answer:

8090 [49]3 years ago

6 0

Answer:

Range: y ≥ 4

Step-by-step explanation:

Range is the y value

y = (x-2)^2 +4

The smallest the squared term can be is zero

y = 0 +4

The smallest y can be is 4

y ≥ 4

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A rectangle has a length that is 2 meters more than the width. The area of the rectangle is 288 square meters. Find the dimensio

Rufina [12.5K]

Answer:

L = 18 and w = 16

Step-by-step explanation:

The area of a rectangle is found by A = l*w. Since the length here is 2 more than the width or 2 + w and the width is w, substitute these values and A = 288 to solve for w.

$A = l*w\\288 = w(2+w)\\288 = w^2 + 2w$

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