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3 years ago

For each question below, identify if first number is divisible by the second number, and if so, the reason why.

1 answer:

7 0

Alright, here are the divisibility rules:
2 -- If the last digit is 0, 2, 4, 6, or 8.
3 -- If the sum of the digits is divisible by 3.
4 -- If the last two digits are divisible by 4.
5 -- If the last digit is 0 or 5.
6 -- If the number is divisible by 2 or 3.
7 -- Cross off the last digit, double it, and subtract. If new number is divisible by 7, the original number is divisible by 7.
8 -- If the last three digits are divisible by 8.
9 -- If the sum of the digits is divisible by 9.
10 -- If the last digit is 0.
11 -- Subtract the last digit from the number formed by the remaining digits. If new number is divisible by 11, the original number is divisible by 11.
12 -- If the number is divisible by 3 and 4.

Let's use these rules to answer your questions.

Is 26 divisible by 2?

Answer: C.

Is 216 divisible by 3?

Answer: B.

Is 40,100 divisible by 10?

Answer: C.

Is 318 divisible by 9?

Answer: A.

Is 87,235 divisible by 5?

Answer: B.

Is 43,121 divisible by 3?

Answer: A.

Is 1,112 divisible by 5?

Answer: A.

Is 10,000,058 divisible by 10?

Answer: A.

Is 94,032 divisible by 9?

Answer: B.

Is 201,086 divisible by 2?

Answer: C.

Well, that answers all of your questions! :)

You might be interested in

Which expression is equivalent to 28 + 7? Prove your answer by showing your work.

OverLord2011 [107]

Answer:

ok so first lets find the answer to the original question

28+7=35

so lets find which one is equal to 35

7(4+1)=28+7=35 yes

4(7+1)=28+4=32 no

4(7+3)=28+12=40 no

7(4+7)=28+49=77 no

a is the answer

Hope This Helps!!!

6 0

3 years ago

HELP PLS FOR BRAINLIEST!

igomit [66]

Answer:

Electric force = 8.20x10⁻⁸ N

Gravitational force = 3.61x10⁻⁴⁷ N

Step-by-step explanation:

1. The electric force can be found using the following equation:

$F_{e} = \frac{Kq_{e}q_{p}}{d^{2}}$

Where:

K: is the Coulomb's constant = 9x10⁹ N.m²/C²

$q_{p}$ : is the charge of the proton = 1.6x10⁻¹⁹ C

$q_{e}$ : is the charge of the electron = -1.6x10⁻¹⁹ C

d: is the distance = 5.3x10⁻¹¹ m

Hence, the magnitude of the electric force is:

$|F_{e}| = \frac{9\cdot 10^{9} N.m^{2}/C^{2}*(-1.6\cdot 10^{-19} C)*1.6 \cdot 10^{-19} C}{(5.3 \cdot 10^{-11} m)^{2}} = 8.20 \cdot 10^{-8} N$

2. The gravitational force can be calculated as follows:

$F_{g} = \frac{Gm_{e}m_{p}}{d^{2}}$

Where:

$m_{e}$ : is the electron's mass = 9.1x10⁻³¹ kg

$m_{p}$ : is the proton's mass = 1.67x10⁻²⁷ kg

G: is the gravitational constant = 6.67x10⁻¹¹ N.m²/kg²

Therefore, the gravitational force is:

$F_{g} = \frac{6.67 \cdot 10^{-11} N.m^{2}/kg^{2}*9.1 \cdot 10^{-31} kg*1.67 \cdot 10^{-27} kg}{(5.3 \cdot 10^{-11} m)^{2}} = 3.61 \cdot 10^{-47} N$

As we can see, the gravitational force is much less than the electric force.

I hope it helps you!

5 0

3 years ago

Help me pleaseeee:(((

pashok25 [27]

Answer:

-10, -11, -13, -15, -20

t≤-10

Step-by-step explanation:

Start by solving for t

-8t≥80

t≤ -10

(we flip the inequality sign because we are dividing by a negative)

Then just select all the numbers that are less than or equal to 10

-10, -11, -13, -15, -20

The equivalent inequality is what we solved for

t≤-10

4 0

3 years ago

Find the value of X rounded to the nearest tenth<br> A)5.1<br> B)9.2<br> C)5.8<br> D)5.2

professor190 [17]

Answer:

Step-by-step explanation:

Chords which intersect have segments whose products are equal. This means the chord with lengths 5 and x has a product 5x. It is equal to the the other chords lengths 5.1 and 9 as a product 5.1*9.

5x = (5.1)(9)

5x = 45.9

x = 9.18

9.18 rounds to the tenth place as 9.2

8 0

3 years ago

(will give 20 pts)

viktelen [127]

Answer:

hablo español

Step-by-step explanation:

4 0

3 years ago