Question

HELP PLS FOR BRAINLIEST!

Answer 1

Answer:

Electric force = 8.20x10⁻⁸ N

Gravitational force = 3.61x10⁻⁴⁷ N

Step-by-step explanation:

1. The electric force can be found using the following equation:

$F_{e} = \frac{Kq_{e}q_{p}}{d^{2}}$

Where:

K: is the Coulomb's constant = 9x10⁹ N.m²/C²      

$q_{p}$: is the charge of the proton = 1.6x10⁻¹⁹ C

$q_{e}$: is the charge of the electron = -1.6x10⁻¹⁹ C

d: is the distance = 5.3x10⁻¹¹ m

Hence, the magnitude of the electric force is:

$|F_{e}| = \frac{9\cdot 10^{9} N.m^{2}/C^{2}*(-1.6\cdot 10^{-19} C)*1.6 \cdot 10^{-19} C}{(5.3 \cdot 10^{-11} m)^{2}} = 8.20 \cdot 10^{-8} N$                

2. The gravitational force can be calculated as follows:

$F_{g} = \frac{Gm_{e}m_{p}}{d^{2}}$

Where:

$m_{e}$: is the electron's mass = 9.1x10⁻³¹ kg

$m_{p}$: is the proton's mass = 1.67x10⁻²⁷ kg

G: is the gravitational constant = 6.67x10⁻¹¹ N.m²/kg²

Therefore, the gravitational force is:

$F_{g} = \frac{6.67 \cdot 10^{-11} N.m^{2}/kg^{2}*9.1 \cdot 10^{-31} kg*1.67 \cdot 10^{-27} kg}{(5.3 \cdot 10^{-11} m)^{2}} = 3.61 \cdot 10^{-47} N$

As we can see, the gravitational force is much less than the electric force.

I hope it helps you!