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3 years ago

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If the balance of supplies at the start of the month was $900 and at the end of the month there was $450 on hand, the adjustment

for Supplies would be A. $450. B. $550. C. $350. D. $900

2 answers:

Westkost [7]3 years ago

4 0

A.450 If the balance of supplies at the start of the month was $900 then at the end of the month it was $450 so the answer would be 450.

Got this answer on weegy you should check it out sometimes

lys-0071 [83]3 years ago

3 0

The correct answer is letter A. $450

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Write the first five terms of the geometric sequence in which a1=64 and the common ratio is 5/4

natita [175]

Remember that finding terms in a geometric sequence is done by multiplying the previous term by a common ratio $r$ . For example, we can say:

$a_2 = a_1 r$

$a_3 = a_2 r = (a_1 r)r = a_1 r^2$

We have $a_1 = 64$ . To find $a_2$ , let's multiply this term by $\frac{5}{4}$ :

$a_2 = 64 \cdot \frac{5}{4} = 80$

Now, let's use this to find all of our other terms:

$a_3 = 80 \cdot \frac{5}{4} = 100$

$a_4 = 100 \cdot \frac{5}{4} = 125$

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8 0

3 years ago

Find all of the eigenvalues λ of the matrix A. (Hint: Use the method of Example 4.5 of finding the solutions to the equation 0 =

Svetradugi [14.3K]

Answer:

$\lambda=8,\ \lambda=-5$

Step-by-step explanation:

<u>Eigenvalues of a Matrix</u>

Given a matrix A, the eigenvalues of A, called $\lambda$ are scalars who comply with the relation:

$det(A-\lambda I)=0$

Where I is the identity matrix

$I=\left[\begin{array}{cc}1&0\\0&1\end{array}\right]$

The matrix is given as

$A=\left[\begin{array}{cc}3&5\\8&0\end{array}\right]$

Set up the equation to solve

$det\left(\left[\begin{array}{cc}3&5\\8&0\end{array}\right]-\left[\begin{array}{cc}\lambda&0\\0&\lambda \end{array}\right]\right)=0$

Expanding the determinant

$det\left(\left[\begin{array}{cc}3-\lambda&5\\8&-\lambda\end{array}\right]\right)=0$

$(3-\lambda)(-\lambda)-40=0$

Operating Rearranging

$\lambda^2-3\lambda-40=0$

Factoring

$(\lambda-8)(\lambda+5)=0$

Solving, we have the eigenvalues

$\boxed{\lambda=8,\ \lambda=-5}$

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3 years ago