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Stels [109]
3 years ago
10

Charlotte has an aquarium in the shape of a rectangular prism. it is 3/4 of a foot high/ 2 and 1/2 feet long, and 1 and 1/4 feet

wide. if she fills it to the top with water, how much water can it hold , in cubic feet.
Mathematics
1 answer:
Anuta_ua [19.1K]3 years ago
3 0
V=xyz

V=0.75(2.5)1.25

V=2.34375 ft^3  or if you want the fraction..

V=2 11/32 ft^3
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Imara used these steps to find the length of the hypotenuse of the right triangle.
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Answer:

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Step-by-step explanation:

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4 0
3 years ago
Solid a is a right, rectangular prism, in other words is a box. The length and width are double to form solid b, but the heigth
tresset_1 [31]

Answer:

The length and width dimensions of solid 'a' are multiplied by 2 while the height remains the same to get the representative quantity in solid, b

Step-by-step explanation:

The given parameters of solid 'a' are;

The shape of solid, a = Right, rectangular prism

Let 'l' represent the length of solid 'a', let 'w' represent the width of solid 'a' and let 'h' represent the height of solid 'a'

We have;

The length of solid, l_b = 2·l

The width of solid, w_b = 2·w

The height of solid, h_b = h

Given that we have;

The length of solid, b = 2 × The length of solid, a

The width of solid, b = 2 × The width of solid, a

The height of solid, b = The height of solid, a

The dimensions of length and width of each quantity in solid 'a' will be multiplied by 2 to find the dimension of a similar quantity in solid 'b'

The change in volume from solid 'a' to solid 'b' is given as follows;

The volume of solid, 'a', Vₐ = l × w × h = l·w·h

The volume of solid, 'b', V_b = 2·l × 2·w ×h = 4·l·w·h

V_b = 4 × Vₐ

Therefore, the volume of each unit volume in solid 'a' is multiplied by 4 to get the volume of the image of the unit volume in solid 'b'

The cross sectional area of solid 'a', Aₐ = l × w

The cross sectional area of solid 'b', A_b = 2·l × 2·w = 4·l·w

A_b = 4 × Aₐ

The cross sectional area of each unit of solid 'a' is multiplied by 4 to get the image of the unit cross sectional area in solid 'b'.

Therefore;

The change in the height and width of of solid 'b' is equal to a change in twice the height and width of solid 'a' at a given height, 'h'

The relationships are;

l_b = 2·l, w_b = 2·w, h_b = h

4 0
3 years ago
PLEASE help me solve this problem
irakobra [83]

Answer:

that looks hard?

Step-by-step explanation:

8 0
3 years ago
What is the product?
konstantin123 [22]

Answer:

-108

Literally just put what you wrote in the calculator

Step-by-step explanation:

4 • (-9) • (-3) • (-1)

5 0
4 years ago
A casino wants to offer a new game with (potentially) spectacular prizes:The player flips a fair coin until they flip heads.The
MissTica

Answer:

The casino should charge for this game at least $1 to break even.

Step-by-step explanation:

We can define the prize function as

M(n)=2^{ n+1}

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The probability of n consecutive tails can be calculated as p^n=0.5^n. The probaility of getting a head after the n consecutive tails is p=0.5, so the probability of having n consecutive tails and a head is p^{n+1}=0.5^{n+1}

Then we can calculate the expected value of M as

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The expected money prize for this game is $1, so the casino should charge to play at least $1 to break even.

4 0
4 years ago
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