Solve the equation.Round to the nearest tenth.
1 answer:
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The answer is really none of the above, because all of these have divisions by difference in x, and there are perfectly fine rectangles where those will mean dividing by zero.
To do the problem the way they want us to, we note segments with the same slope are parallel (or collinear); segments with slopes which multiply to -1 are perpendicular.
Let's figure out what each choice is trying to tell us by translating it into parallel and perpendicular. Remember A is point 1, ...
A. ((y_4-y_3)/(x_4-x_3)= (y_3-y_2)/(x_3-x_2)) and ((y_4-y_3)/(x_4-x_3)×(y_3-y_2)/(x_3-x_2))=-1
translated, that's CD║BC and CD⊥BC - contradictory; second half right
B. (y_4-y_3)/(x_4-x_3)= (y_2-y_1)/(x_2-x_1) and ((y_4-y_3)/(x_4-x_3)×(y_2-y_1)/(x_2-x_1))=-1
CD ║ AB and CD ⊥ AB - only the parallelogram half is right
C. (y_4-y_3)/(x_4-x_3)= (y_2-y_1)/(x_2-x_1) and (y_4-y_3)/(x_4-x_3)×(y_3-y_2)/(x_3-x_2)=-1
CD║AB and CD⊥BC - that's TRUE
D. (y_4-y_3)/(x_4-x_3)= (y_3-y_1)/(x_3-x_1) and (y_4-y_3)/(x_4-x_3)×(y_2-y_1)/(x_2-x_1)=-1
CD║AC and CD⊥AB - nope
Answer: C
The way I'd get the proper expression is with the dot product.
A parallelogram is a rectangle when adjacent sides are perpendicular. It only takes one right angle to make them all right.
Two sides are perpendicular when the dot product of their direction vectors is zero. All the answers have so one side is CD. The other side must be BC or AD; AD would give
terms which don't appear among the answer, so let's go with BC.
The direction vectors are
For perpendicularity we need a zero dot product:
That's the correct expression, given it's a parallelogram, to demonstrate it's a rectangle. The divisions make it iffy.
Answer:
1) (2.2, -1.4)
2) (1.33, 1)
Step-by-step explanation:
Question 1)
Two lines, with their corresponding equations are given and we have to find the solution to the system of equations.
The given lines are:
Equation of Line 1:
This line passes through the points: (0, 2.5) , (2.2, -1.4)
Equation of Line 2:
This line passes through the points (0, -3) , (2.2, -1.4)
By looking at the graph/given data we have to find the solution of these linear equations.
Remember that the solution of linear equations is an ordered pair, through which both the lines pass i.e. the point at which both the given lines intersect is the solution of the linear equations.
From the given data we can see that both the lines pass through one common point, (2.2, -1.4). Since, both lines pass through this point, this means this is the point of intersection of the lines and hence there solution.
So, the answer to this questions is (2.2, -1.4)
Question 2)
The given equations are:
y = 1.5x - 1 Equation 1
y = 1 Equation 2
We can solve these equations by method of substitution.
Substituting the value of y from Equation 2, in Equation 1, we get:
1 = 1.5x - 1
1 + 1 = 1.5x
2 = 1.5x
x = 2/1.5
x = 1.33
y = 1
Thus, the solution of the given linear equations is (1.33, 1)