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drek231 [11]
3 years ago
9

I really don't know how to do this

Mathematics
1 answer:
Vaselesa [24]3 years ago
7 0
When it comes to finding points on a graph, think of the saying, "you have to learn how to walk before you climb." 

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Find the following: F(x, y, z) = e^(xy) sin z j + y tan^−1(x/z)k Exercise Find the curl and the divergence of the vector field.
natulia [17]

\vec F(x,y,z)=e^{xy}\sin z\,\vec\jmath+y\tan^{-1}\dfrac xz\,\vec k

Divergence is easier to compute:

\mathrm{div}\vec F=\dfrac{\partial(e^{xy}\sin z)}{\partial y}+\dfrac{\partial\left(y\tan^{-1}\frac xz\right)}{\partial z}

\mathrm{div}\vec F=xe^{xy}\sin z-\dfrac{xy}{x^2+z^2}

Curl is a bit more tedious. Denote by D_t the differential operator, namely the derivative with respect to the variable t. Then

\mathrm{curl}\vec F=\begin{vmatrix}\vec\imath&\vec\jmath&\vec k\\D_x&D_y&D_z\\0&e^{xy}\sin z&y\tan^{-1}\frac xz\end{vmatrix}

\mathrm{curl}\vec F=\left(D_y\left[y\tan^{-1}\dfrac xz\right]-D_z\left[e^{xy}\sin z\right]\right)\,\vec\imath-D_x\left[y\tan^{-1}\dfrac xz\right]\,\vec\jmath+D_x\left[e^{xy}\sin z}\right]\,\vec k

\mathrm{curl}\vec F=\left(\tan^{-1}\dfrac xz-e^{xy}\cos z\right)\,\vec\imath-\dfrac{yz}{x^2+z^2}\,\vec\jmath+ye^{xy}\sin z\,\vec k

5 0
3 years ago
Find the value of the indicated angles. HELP PLEASE!!
balu736 [363]

Answer:

52

Step-by-step explanation:

add add add add add add adddaddd addda

7 0
3 years ago
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Which graph shows the line that best fits the data points given?
stiv31 [10]
U probably need to add in a picture
4 0
3 years ago
Whats the prime factorization for 640
ahrayia [7]
The prime factorization of 640 can be written as 27 × 51 where 2, 5 are prime.
3 0
2 years ago
What is the value of a?
pantera1 [17]

Answer:

a=25

Step-by-step explanation:

since angle T is 60, and angle Y is the exact same as T, it would make sense that a=25 [3(25)-15]

4 0
3 years ago
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