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drek231 [11]
3 years ago
9

I really don't know how to do this

Mathematics
1 answer:
Vaselesa [24]3 years ago
7 0
When it comes to finding points on a graph, think of the saying, "you have to learn how to walk before you climb." 

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What is the area of this triangle 8m and 6m
mr_godi [17]
Area for triangles is 1/2b * h.

If 8m were the height, then the area is 24 sq m.

If 6m were the height, then the area is still 24 sq m.

The area is 24 sq m.

Hope this helps! Have a great day :)




4 0
3 years ago
Suppose that 10% of all homeowners in an earthquake-prone area of California are insured against earthquake damage. Four homeown
guapka [62]

Remainder of question:

Find the probability distribution of x

Answer:

The random variable x is defined as: X = {0, 1, 2, 3, 4}

The probability distribution of X:

P(X = 0) = 0.656

P(X = 1) = 0.2916

P(X= 2) = 0.0486

P(X=3) = 0.0036

P(X = 4) = 0.0001

Step-by-step explanation:

Sample size, n = 4

Random variable, X = {0, 1, 2, 3, 4}

10% (0.1) of the homeowners are insured against earthquake, p = 0.1

Proportion of homeowners who are not insured against earthquake, q = 1 - 0.1

q = 0.9

Probability distribution of x,

P(X = r) = ^nC_r *p^r q^{n-r} \\\\P(X= 0) =(^4C_0 *p^1 q^4 )\\P(X=0) = (^4C_0 *0.1^0 0.9^4 ) = 0.656\\P(X= 1)= (^4C_1 *p^1 q^3 )\\P(X=1) = (^4C_1 *0.1^1 0.9^3 ) = 0.2916\\P(X= 2)=( ^4C_2 *p^2 q^2) \\P(X=2) = (^4C_2 *0.1^2 0.9^2 ) = 0.0486\\P(X= 3) = (^4C_3 *p^3 q^3) \\ P(X=3) = (^4C_3 *0.1^3 0.9^1 ) = 0.0036\\P(X= 4) =  (^4C_4 *p^4 q^0 )\\ P(X=4) =(^4C_4 *0.1^4 0.9^0 ) = 0.0001

5 0
3 years ago
Please ANSWER! DOING A TEST!
Natasha_Volkova [10]

Answer:

The correct answer is B!

Step-by-step explanation:

6 0
3 years ago
I need help with both
Nookie1986 [14]
Hey There

According to me, 
no 1 is 
SQUARE

no. 2 is 
CONGRUENT

HOPE THIS HELPS
3 0
3 years ago
Read 2 more answers
8-2x<4 solve inequality
Andreas93 [3]

Answer:

x > 2

x ∈ ( +2 ; + oo )

Step-by-step explanation:

8 - 2x < 4

8 - 4  < 2x

4 < 2x | : 2

2 < x

x > 2

x ∈ ( +2 ; + oo )

6 0
3 years ago
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