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Vera_Pavlovna [14]
3 years ago
6

Which equation represents this situation?

Mathematics
2 answers:
Tatiana [17]3 years ago
8 0
The answer would be h+(h+2.5)=22
The h represents Williams hours and the h+22 represents jose's hours. Together, they add to 22 hours :)
Hope this helps!
user100 [1]3 years ago
6 0
The answer would be h + (h+2.5)= 22. H represents the number of hours William worked. H+2.5 represents the number of hours José worked because he worked 2.5 more hours (H) than William so you add 2.5 to William's hours worked. You then add both together to get the total of 22 hours.
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6 0
3 years ago
(3 + 4i) + (5 − 2i) (2 points) −2 + 6i 2 − 2i 7 + 3i 8 + 2i
k0ka [10]

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6 0
2 years ago
A particle moves on a straight line and has acceleration a(t)=24t+2. Its position at time t=0 is s(0)=3 and its velocity at time
user100 [1]

Answer:

It's position at time t = 5 is 593.

Step-by-step explanation:

The velocity v(t) is the integral of the acceleration a(t)

The position s(t) is the integral of the velocity v(t)

We have that:

The acceleration is:

a(t) = 24t + 2

Velocity:

v(t) = \int {a(t)} \, dt = \int {24t + 2} \, dt = 12t^{2} + 2t + K

K is the initial velocity, that is v(0). Since V(0) = 13, K = 13

Then

v(t) = 12t^{2} + 2t + 13

Position:

s(t) = \int {s(t)} \, dt = \int {12t^{2} + 2t + 13} \, dt = 4t^{3} + t^{2} + 13t + K

Since s(0) = 3

s(t) = 4t^{3} + t^{2} + 13t + 3

What is its position at time t=5?

This is s(5).

s(t) = 4t^{3} + t^{2} + 13t + 3

s(5) = 4*5^{3} + 5^{2} + 13*5 + 3

s(5) = 593

It's position at time t = 5 is 593.

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Answer:

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