2a^2b^3(4a^2+3ab^2-ab)=?
<span>
is what I presume you actually meant. </span>
<span>
Pull out the common factors of (4a^2+3ab^2-ab) and you will get </span>
<span>
a(4a+3b^2 -b) </span>
Substitute this back into the original equation and you get
<span>
2a^2b^3[a(4a+3b^2-b)] = </span>
2a^3b^3(4a+3b^2-b) =
<span>2a^3b^3(4a-b+3b^2)
</span>
Just work through step by step
Follow each point until you reach one answer
Digits = 7
-9 = reverse
16 - 9 = 7 x
25 - 9 = 16 x
34 - 9 = 25 x
43 - 9 = 34 Y
52 - 9 = 43 x
61 - 9 = 52 x
4 + 3 = 7
43 - 9 = 34 - the digits have been reversed
43
Substitute the given value into the function and evaluate.
The answer is -10