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3 years ago

2. Find the equation of the line that is perpendicular to the line y = -1/3 x - 5 and passes through the point (12, 0).

Mathematics

1 answer:

Leokris [45]3 years ago

7 0

The answer is y = 3x - 36

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Quadrilateral DUCKDUCKD, U, C, K is inscribed in circle OOO. What is the measure of \angle K∠Kangle, K?

N76 [4]

Answer:

Measure of ∠K=180-∠U

Measure of ∠K=1/2m(arc DUC)

Step-by-step explanation:

Given:

DUCK quadrilateral inscribed in circle with center O

To Find:

Measure angle K

Solution:

Here the Quadrilateral in inscribed in a circle with center O named as DUCK

So angle K and U are opposite to each other

We know that the angle of Quadrilateral inscribed in a circle are supplemenatry angles

Hence

∠U+∠K=180

Or The ∠K=1/2*m∠arc(DUC).

Hence depending on the given value for arc measure or angle of quadrilateral we calculate the angle K

5 0

2 years ago

Read 2 more answers

How do I do number three help pleaseeeeeeee

posledela

I got 36. I did 5-2=3, 3•180=540, 540/5=108, 180-108=72, and 72/2= 36

4 0

2 years ago

A dairy produces 256 pints of milk each day. How many gallons of milk is this? (1 gallon

hoa [83]

Answer:

32 gallons

Step-by-step explanation:

c'mon this is simple, but thx for the points

6 0

2 years ago

Consider a 15-year mortgage at an interest rate of 8% compounded monthly. The amount to be mortgaged is $130,000. After the firs

MrMuchimi

The answer is <span>$129,624.32</span>

3 0

2 years ago

<img src="https://tex.z-dn.net/?f=f%28x%29%20-%20%5Cfrac%7Bx%5E%7B2%7D-4%20%7D%7Bx%5E%7B4%7D%20%2Bx%5E%7B3%7D%20-4x%5E%7B2%7D-4%

Llana [10]

a) The given function is

$f(x)=\frac{x^2-4}{x^4+x^3-4x^2-4}$

The domain refers to all values of x for which the function is defined.

The function is defined for

$x^4+x^3-4x^2-4\ne0$

This implies that;

$x\ne -2.69,x\ne 1.83$

b) The vertical asymptotes are x-values that makes the function undefined.

To find the vertical asymptote, equate the denominator to zero and solve for x.

$x^4+x^3-4x^2-4=0$

This implies that;

$x= -2.69,x=1.83$

c) The roots are the x-intercepts of the graph.

To find the roots, we equate the function to zero and solve for x.

$\frac{x^2-4}{x^4+x^3-4x^2-4}=0$

$\Rightarrow x^2-4=0$

$x^2=4$

$x=\pm \sqrt{4}$

$x=\pm2$

The roots are $x=-2,x=2$

d) The y-intercept is where the graph touches the y-axis.

To find the y-inter, we substitute;

$x=0$ into the function

$f(0)=\frac{0^2-4}{0^4+0^3-4(0)^2-4}$

$f(0)=\frac{-4}{-4}=1$

e) to find the horizontal asypmtote, we take limit to infinity

$lim_{x\to \infty}\frac{x^2-4}{x^4+x^3-4x^2-4}=0$

The horizontal asymtote is $y=0$

f) The greatest common divisor of both the numerator and the denominator is 1.

There is no common factor of the numerator and the denominator which is at least a linear factor.

Therefore the function has no holes.

g) The given function is a proper rational function.

There is no oblique asymptote.

See attachment for graph.

6 0

2 years ago