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OLEGan [10]
3 years ago
9

2. Find the equation of the line that is perpendicular to the line y = -1/3 x - 5 and passes through the point (12, 0).

Mathematics
1 answer:
Leokris [45]3 years ago
7 0
The answer is y = 3x - 36
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2 whole 2/3 times 3/11
sashaice [31]
2 2/3 x 3/11
= 8/4 x 3/11
= 24/44
Simplified
6/11
3 0
3 years ago
Y=2/7 -7 y=-x+2 What is the solution for this system of equations?​
bulgar [2K]

Answer:

(61/7, -47/7)

Step-by-step explanation:

Given: y=2/7 -7

           y=-x+2

Rewrite the top equation ( y=2/7 -7

y = -47/7

y = -x + 2

Because both equations are equal to y, we can rewrite it again.

-47/7 = -x + 2

Add x to both sides

x + (-47/7) = 2

Add 47/7 to both sides.

x = 47/7 + 2/1

x = 61/7

As stated in the beginning, y is equal to -47/7

Hope you understand!

5 0
2 years ago
P plus (negative 9)= thirty three
Cloud [144]

Answer:

42

Step-by-step explanation:

33+9=42

42-9=33

5 0
3 years ago
the eccentricity of a hyperbola is defined as e=c/a. find an equation with vertices (1,-3) and (-3,-3) and e=5/2
Ksivusya [100]

Answer:

\frac{(x + 1 )^{2} }{4} - \frac{(y + 3 )^{2} }{21} = 1.

Step-by-step explanation:

If (α, β) are the coordinates of the center of the hyperbola, then its equation of the hyperbola is \frac{(x - \alpha )^{2} }{a^{2} } - \frac{(y - \beta )^{2} }{b^{2} } = 1.

Now, the vertices of the hyperbola are given by (α ± a, β) ≡ (1,-3) and (-3,-3)

Hence, β = - 3 and α + a = 1 and α - a = -3

Now, solving those two equations of α and a we get,  

2α = - 2, ⇒ α = -1 and

a = 1 - α = 2.

Now, eccentricity of the hyperbola is given by b^{2} = a^{2}(e^{2}  - 1) = 4[(\frac{5}{2} )^{2} -1] = 21 {Since e = \frac{5}{2} given}

Therefore, the equation of the given hyperbola will be  

\frac{(x + 1 )^{2} }{4} - \frac{(y + 3 )^{2} }{21} = 1. (Answer)

6 0
2 years ago
The school sold $6000 worth of tickets. Adult tickets were seven dollar and children’s tickets were three dollars. Three times a
padilas [110]

Answer:

1,500 tickets in total (375 adult tickets and 1,125 children tickets)

Step-by-step explanation:

Let x be the number of adult tickets sold.

Three times as many children tickets were sold as adults, so 3x is the number of children tickets sold.

Children tickets were three dollars, so 3x children tickets cost \$3\cdot 3x=\$9x.

Adult tickets were seven dollar, so x adult tickets cost \$7\cdot x=\$7x.

The school sold $6000 worth of tickets.

Hence,

9x+7x=6,000\\ \\16x=6,000\\ \\x=\dfrac{6,000}{16}=375\\ \\3x=1,125\\ \\x+3x=375+1,125=1,500

7 0
2 years ago
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