The answer to the question is C
3 odd integers have a property that they average up to the middle large one. Let's say we have 3, 5, and 7. 3 is 2 less than 5 and 7 is 2 more than 5. so when you add them it equals 2 times 5.
After we know that, the sum of 3 odd integers is just 3 times the middle number. ex. 3+5+7 = 3 times 5 = 15
Then we know the some number times three = 225. we find out that the middle number is 75, so the other two are 73 and 77
The input is known as x and the output is known as y in math.
So you’re stating that we’re making the equation equal the output, y, and we’re adding based off of the word “more”. Now that we know we’re adding, we have to find what we are adding together. We are adding x and 11 is that it equals y. Note that x and y could be many different variables and values.
Y= x+11
T us assume the two numbers to be "x" and "y".
Then
2x + y = 310
And
x - y = 55
Let us take the second equation and find the value of x in relation to y.
x - y = 55
x = y + 55
Now let us put the value of x in the first equation, we get
2x + y = 310
2(y + 55) + y = 310
2y + 110 + y = 310
3y = 310 - 110
3y = 200
y = 200/3
= 66 2/3
Now putting the value of y in the second equation, we get
x - y = 55
x - (200/3) = 55
3x - 200 = 55 * 3
3x = 165 + 200
x = 365/3
= 121 2/3
So the value of x is 121 2/3 and the value of y is 66 2/3
Hey there :)
( 2x⁵ - 3x⁴ + x² + 5x + 7 ) - ( - 4x⁵ - x⁴ - 3x² - 5x + 2 )
Let us combine like-terms
2x⁵ - ( - 4x⁵ ) - 3x⁴ - ( - x⁴ ) + x² - ( - 3x² ) + 5x - ( - 5x ) + 7 - 2
Minus and minus becomes plus
2x⁵ + 4x⁵ - 3x⁴ + x⁴ + x² + 3x² + 5x + 5x + 7 -2
6x⁵ - 2x⁴ + 4x² + 10x + 5
Your answer will be option A) 6x⁵ - 2x⁴ + 4x² + 10x + 5
