When radicals (square roots) include variables, they are still simplified the same way. We just have to work with variables as well as numbers
1) Factor the radicand (the numbers/variables inside the square root). Factor the number into its prime factors and expand the variable(s).
2) Bring any factor listed twice in the radicand to the outside
Answer:
a) x^3y2
b) 6x^2y^3
Step-by-step explanation:
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Answer:</u></h3>
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Step-by-step explanation:</u></h3>
<em>There can be many ways to find the number.</em><em> I have found the number with the help of fractions and multiplication. </em><em>Below is the solution to your problem.</em>
- 80 = 20/100
- => 5 x 80 = 20 x 5/100
- => 400
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Conclusion:</u></h3>
<em>Hence, 80 is 20% of 400. </em><em>I hope my method helped you.</em>

F ( x ) = 6^(x+1)
y = 6^(x+1)

The inverse is:

And when you plug in the values: x = 1, y = - 1:
- 1 = log 1 - 1
- 1 = 0 - 1
- 1 = - 1
so the answer is:
( 1, - 1 )