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Rama09 [41]
3 years ago
9

7 less than-2 times x is greater than or equal to 41

Mathematics
1 answer:
umka21 [38]3 years ago
6 0

Written out that's 2x-7 is greater than or equal to 41. Add 7 to both sides to get 2x is greater than or equal to 48. Divide both sides by 2 to get that x is greater than or equal to 24.

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Kristen was asked to write each of the numbers in the expression 80,000 x 25 using exponents. Her response was (8 x 10 to the po
Gnom [1K]

Kriste respone is wrong

<em><u>Solution:</u></em>

Given that,

Kristen was asked to write each of the numbers in the expression 80,000 x 25 using exponents

Her response was (8 x 10 to the power of 3) x 5 to the power of 2

No, the response of Kristen is wrong

Let us first understand about exponents

An exponent refers to the number of times a number is multiplied by itself

Given expression is:

80000 \times 25

Here, 80000 has 4 zeros

Therefore, it can be raised as 10 power 4

80000 = 8 \times 10^4

<em><u>Thus the expression becomes:</u></em>

80000 \times 25 = 8 \times 10^4 \times 25

Also, 25 can be written as 5 power 2

80000 \times 25 = 8 \times 10^4 \times 5^2

Thus given expression is written as (8 x 10 to the power 4) x 5 power to the power 2

Thus Kristen respone is wrong, because he has raised 10 to power 3

6 0
3 years ago
ABCD is a parallelogram. if side AB=6x-10, side BC=4x-5, and side CD =3x+5, find the value of x
serg [7]

Answer:

x=5

Step-by-step explanation:

If ABCD is a parallelogram, then AB = CD

AB=CD

6x-10 = 3x+5

Subtract 3x from each side

6x-3x -10 = 3x-3x+5

3x-10 = 5

Add 10 to each side

3x-10+10 = 5+10

3x = 15

Divide by 3 on each side

3x/3 =15/3

x=5


8 0
3 years ago
Determine the value of y, if x is 5.<br> y = |x|– 10<br> Answer :
n200080 [17]
Y = -5

work:

y = |5| - 10

y = 5 - 10

y = -5
8 0
4 years ago
Read 2 more answers
1.) A 20° sector in a circle has an area of 21.5π yd².
a_sh-v [17]

<u>Part 1)</u> A 20° sector in a circle has an area of 21.5π yd².

What is the area of the circle?  

we know that

the area of a circle represent a sector of 360 degrees

so by proportion

\frac{21.5\pi }{20} =\frac{x}{360} \\ \\ x*20=360*21.5\pi \\ \\x=(360*21.5*3.14)/20\\ \\x= 1,215.18\ yd^{2}    

therefore

<u>the answer part 1) is</u>

The area of the circle is 1,215.18\ yd^{2}

<u>Part 2)</u> What is the area of a sector with a central angle of 3π/5 radians and a diameter of 21.2 cm?

we know that

the area of the circle is equal to

A=\pi r^{2}

where

r is the radius of the circle

in this problem we have

Diameter=21.2\ cm\\ r=Diameter/2\\r=21.2/2\\r= 10.6\ cm

<u>Find the area of the circle</u>

A=\pi r^{2}

A=\pi*10.6^{2}

A=352.8104\ cm^{2}

<u>Find the area of the sector</u>

we know that the area of the circle represent a sector of 2\pi radians

by proportion

\frac{352.8104}{2\pi }=\frac{x}{(3\pi/5)} \\\\x*2\pi=(3\pi*352.8104)/5\\ \\x= 105.84\ cm^{2}

therefore

<u>the answer part 2) is</u>

the area of the sector is

105.84\ cm^{2}

7 0
3 years ago
ПОЖАЛУЙСТА ПОМОГИТЕ РЕШИТЬ ДАЮ 23 ОЧКА!!!
posledela

(Простите, пожалуйста, мой английский. Русский не мой родной язык. Надеюсь, у вас есть способ перевести это решение. Если нет, возможно, прилагаемое изображение объяснит достаточно.)

Use the shell method. Each shell has a height of 3 - 3/4 <em>y</em> ², radius <em>y</em>, and thickness ∆<em>y</em>, thus contributing an area of 2<em>π</em> <em>y</em> (3 - 3/4 <em>y</em> ²). The total volume of the solid is going to be the sum of infinitely many such shells with 0 ≤ <em>y</em> ≤ 2, thus given by the integral

\displaystyle 2\pi \int_0^2 y \left(3-\frac34 y^2\right) \,\mathrm dy = 2\pi \left(\frac32 y^2 - \frac3{16} y^4\right)\bigg|_0^2 = 6\pi

Or use the disk method. (In the attachment, assume the height is very small.) Each disk has a radius of √(4/3 <em>x</em>), thus contributing an area of <em>π</em> (√(4/3 <em>x</em>))² = 4<em>π</em>/3 <em>x</em>. The total volume of the solid is the sum of infinitely many such disks with 0 ≤ <em>x</em> ≤ 3, or by the integral

\displaystyle \pi \int_0^3 \left(\sqrt{\frac43x}\right)^2 \,\mathrm dx = \frac{2\pi}3 x^2\bigg|_0^3 = 6\pi

Using either method, the volume is 6<em>π</em> ≈ 18,85. I do not know why your textbook gives a solution of 90,43. Perhaps I've misunderstood what it is you're supposed to calculate? On the other hand, textbooks are known to have typographical errors from time to time...

8 0
3 years ago
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