If the -8 is under the square root, then...
OR
If the -8 is not under the square root, then...
Either way, we replace x with -3 and simplify.
For more information, refer to the direct substitution rule for limits.
Dy/dx=2x+2
So velocity will be zero when 2x+2=0, x=-1
Since d2y/dx2=2, it has a constant positive acceleration of 2, so that when dy/dx=0 it is at an absolute minimum value for f(x), which is also the vertex.
y(-1)=1-2+3=2
So the vertex is at (-1,2), which is an absolute minimum so the parabola opens upwards.
And by symmetry we can say that f(0)=f(-2)=3 so you have another two points that you can see (-2,3) and (0,3)
Answer:
Δ AXY is not inscribed in circle with center A.
Step-by-step explanation:
Given: A circle with center A
To find: Is Δ AXY inscribed in circle or not
A figure 1 is inscribed in another figure 2 if all vertex of figure 1 is on the boundary of figure 2.
Here figure 1 is Δ AXY with vertices A , X and Y
And figure 2 is Circle.
Clearly from figure, Vertices A , X and Y are not on the arc/boundary of circle.
Therefore, Δ AXY is not inscribed in circle with center A.
The quotient is 0.20125.
Solution:
Divide .03220 by .16
This can be written as
To divide this, we first remove the decimal term.
To remove decimal in denominator multiply and divide by 100.
Now, divide 3.22 by 16.
The quotient is 0.20125.
The image of the long division is attached below.
Because if you know where the line crosses the y axis (the y intercept) you can plot a point there. Then with slope you can count to your next plotted point. With the 2 points you can now draw your line.
