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4 years ago

8

Brooke has to set up 70 chairs in equal rows for the class talent show. But there is not room for more than 20 rows. What are th

e possible number of rows that Brooke could set up?

1 answer:

earnstyle [38]4 years ago

3 0

14 rows
10 rows
7 rows
5 rows

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Three fair coins are flipped. What is the probability that at least 2 of them come up heads?

exis [7]

Answer:

<h3>The probability that atleast 2 of them come up heads is 0.5</h3><h3>∴ P(A)=0.5</h3>

Step-by-step explanation:

Given that three fair coins are flipped.

<h3>To find the probability that at least 2 of them come up heads:</h3>

Sample space for the given event is

$S={\{HHH, HHT, HTH, HTT, THH, THT, TTH, TTT}\}$

<h3>∴ n(S)=8</h3>

Let A be the events of getting atleast 2 Heads and is given by

A = {HHH, HHT, HTH, THH}

<h3>∴ n(A)=4</h3>

Probability of Getting atleast 2 Heads in 3 Coin Tosses is

$P(A)=\frac{n(A)}{n(S)}$

$P(A)=\frac{4}{8}$

$=0.5$

<h3>∴ P(A)=0.5</h3><h3>∴ the probability that atleast 2 of them come up heads is 0.5</h3>

5 0

4 years ago

Find the value of Y in -3y=12

alexandr1967 [171]

-3y = 12 1) divide -3 on both sides

y = -4

Hope this helps!!!

7 0

4 years ago

Please help me I need ASAP

gtnhenbr [62]

Answer:

Hope it helps

if you need more explanation, just ask

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3 years ago

Let U = {q, r, s, t, u, v, w, x, y, z} A = {q, s, u, w, y} B = {q, s, y, z} C = {v, w, x, y, z}. List the elements in the set: A

gtnhenbr [62]

Answer:

$A \cup C=\left \{ \text{q, s, u, v, w, x, y, z} \right \}$

Step-by-step explanation:

Given: $\text{U}=\left \{\text{q, r, s, t, u, v, w, x, y, z} \right \}$ , $\text{A}=\left \{\text{q, s, u, w, y} \right \}$ , $\text{B}=\left \{\text{q, s, y, z} \right \}$ ,

$\text{C}=\left \{\text{v, w, x, y, z} \right \}$ .

To find: The elements in the set $A \cup C$ .

Solution:

We have,

$\text{U}=\left \{\text{q, r, s, t, u, v, w, x, y, z} \right \}$

$\text{A}=\left \{\text{q, s, u, w, y} \right \}$

$\text{B}=\left \{\text{q, s, y, z} \right \}$

$\text{C}=\left \{\text{v, w, x, y, z} \right \}$

Now, $A \cup C$ will contain all the elements in the set $A$ and all the elements in set $C$ .

So, $A \cup C=\left \{ \text{q, s, u, v, w, x, y, z} \right \}$ .

Hence, $A \cup C=\left \{ \text{q, s, u, v, w, x, y, z} \right \}$ .

7 0

3 years ago

Can't show it all but someone help me out on this

Oksanka [162]

Answer:

I am pretty sure it is the first one

Step-by-step explanation:

Because it is (1, 6) on the graph

Sooooooo. . . ye!

(I'm sorry I couldn't explain more detailed)

6 0

3 years ago

Read 2 more answers