A plane leaves airport A and travels 570 miles to airport B on a bearing of Upper N 32 degrees Upper E. The plane later leaves a
irport B and travels to airport C 390 miles away on a bearing of Upper S 73 degrees Upper E. Find the distance from airport A to airport C to the nearest tenth of a mile.
1 answer:
Answer:
769.46 miles
Step-by-step explanation:
Please have a look at the photo attached in this answer
The missing part of the angle is 32 degrees, so the total angle of B is:
32 + 73 = 105 degrees.
Let x is the distance from airport A to airport C to the nearest tenth of a mile, we use cosine law to find x:
=
- 2(570)(390)cos(105)
<=> = 592070
<=> x = = 769.46 miles
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Critical probability is the essentially cut-off value. The critical probability when the confidence level of 58% is 0.79.
<h3>What is the critical probability?</h3>Critical probability is the essentially cut-off value that defines the region where the test statistic is unlikely to lie.
As it is given that the confidence level is 58%. therefore, in order to calculate the critical probability, we need to calculate the margin of error within a set of data, and it is given by the formula
where the value of the α is expressed as,
Now, as the confidence interval is given to us, therefore, the value of the alpha can be written as,
Further, the critical probability, assuming a confidence level of 58% is,
Hence, the critical probability is 0.79.
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