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Romashka-Z-Leto [24]
3 years ago
6

What is the mode of 1 2 3 4 5 6 7 8 9 10 11

Mathematics
2 answers:
AnnZ [28]3 years ago
8 0

Answer:

In this set of numbers there is no mode

Step-by-step explanation:

<u>Mode of a set of numbers</u>

The number in which repeating more times in a set of numbers.

It is given a set of number

1, 2, 3, 4, 5, 6, 7, 8, 9, 10 and  11

To find the mode of set of numbers

Here all the numbers are at only one times. There is no repetition of any number. Therefore the given set of numbers have no mode.

cluponka [151]3 years ago
6 0

So the mode in this would be none since there arent any doubles of any number

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20% of the girls in class have blonde hair. 16 girls do not have blonde hair. How many total students
yawa3891 [41]
The problem is to find how many students have either blond hair or glasses and then divide that by the total number of students; that will find the probability.
Since 7 have blonde hair and 9 have glasses, that would be a total of 16 persons if there were no overlap; that is, no blonde wears glasses and nobody who wears glasses is a blonde.
But there are 4 persons who have both blond hair and wears glasses. That means, of the 7 who are blondes, 3 of them do not wear glasses. And, of the 9 who wear glasses, 5 of them are not blondes.
So we have 3 who are blondes without glasses, 5 who wear glasses who are not blondes, and 4 blonds with glasses, for a total of 12 persons.
The probability is, therefore, 12/26 or 6/13.
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3 years ago
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Answer:

5pi

Step-by-step explanation:

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3 years ago
Restless Leg Syndrome and Fibromyalgia
Anna11 [10]

Answer:

The probability that a person with restless leg syndrome has fibromyalgia is 0.183.

Step-by-step explanation:

Denote the events as follows:

<em>F</em> = a person with fibromyalgia

<em>R</em> = a person having restless leg syndrome

The information provided is as follows:

P (R | F) = 0.33

P (R | F') = 0.03

P (F) = 0.02

Consider the tree diagram attached below.

Compute the probability that a person with restless leg syndrome has fibromyalgia as follows:

P(F|R)=\frac{P(R|F)P(F)}{P(R|F)P(F)+P(R|F')P(F')}

            =\frac{(0.33\times 0.02)}{(0.33\times 0.02)+(0.03\times 0.98)}\\\\=\frac{0.0066}{0.0066+0.0294}\\\\=0.183333\\\\\approx 0.183

Thus, the probability that a person with restless leg syndrome has fibromyalgia is 0.183.

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3 years ago
five consecutive terms of an arithmetic sequence have a sum of 40. The product of the middle and the two end terms is 224. Find
ratelena [41]
Let the five terms be: a, a + d, a + 2d, a + 3d, a + 4d, then
a + a + d + a + 2d + a + 3d + a + 4d = 5a + 15d = 40
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Also, (a + 2d)(a + 3d)(a + 4d) = 224
(a + 3d - d)(a + 3d)(a + 3d + d) = 224
(8 - d)(8)(8 + d) = 224
(8 - d)(8 + d) = 224/8 = 28
64 - d^2 = 28
d^2 = 64 - 28 = 36
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