Which of the following polynomials is the expansion of (1/2x-y)^4

Mathematics

1 answer:

RideAnS [48]4 years ago

7 0

Answer:

Hello :

(1/2x-y)^4 = (1/2x-y)²(1/2x-y)²

but : (1/2x-y)²= (1/2)²- 2(1/2)xy +y²

so : (1/2x-y)^4 = ((1/2)²- 2(1/2)xy +y²) ((1/2)²- 2(1/2)xy +y²) = ........

You might be interested in

Find the area of circle Q in terms of x

mezya [45]

Answer:

The answer is C 100πcm^3

8 0

3 years ago

Cora said that (5b)^2 = 10b^2. <br> Describe her mistake and state the correct answer.

klio [65]

The easiest answer I know is if you swap the $b$ s with $x$ s, then there will be two equations called parabolas. They open upward if the value is positive and open downward if the value is negative. If the exponent is 2, then it's a parabola. If it's 3, then it's a cubic function, because cube is for "3". Square is for "2". If you look at both parabolas, you can see that $10x^2$ is wider than $(5x)^2$ .

So the best answer I can think of is She made a mistake because the parabola on the 10x² graph is wider than the (5x)² graph. Also, it's because 5x and 10x are not the same thing. When an x value increases, the graph is narrower.

7 0

3 years ago

Which line segment is a diameter of circle L?

dexar [7]

Answer:

The line segment HK is the diameter.

Step-by-step explanation:

A straight line segment that passes through the center of the circle, and whose endpoints lie on its circumference, represents the diameter of the circle.

From the choices given, we see that two straight segments HK and GJ pass through the center of the circle, and have endpoints at the circumference. and since choice GJ is not given in the options, we choose HK as the right diameter of the circle.

<em>P.S: looking at other choices, we see that the segment GK represents the chord, JL represents the radius, and IL also represents the radius.</em>

6 0

4 years ago

Read 2 more answers

Find each x-value at which f is discontinuous and for each x-value, determine whether f is continuous from the right, or from th

fredd [130]

Using continuity concepts, the answers are given by:

The function is right-continuous at x = 0.

The function is left-continuous at x = 1.

------------------------------------

A function f(x) is continuous at x = a if:

$\lim_{x \rightarrow a^{-}} f(x) = \lim_{x \rightarrow a^{+}} f(x) = f(a)$

If $\lim_{x \rightarrow a^{-}} f(x) = f(a)$ , the function is left-continuous.
If $\lim_{x \rightarrow a^{+}} f(x) = f(a)$ , the function is right-continuous.
For the given function, the continuity is tested at the points in which the definitions are changed, x = 0 and x = 1.