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3 years ago

6

Will give brainliest

1 answer:

Alexus [3.1K]3 years ago

7 0

-45.6 is the answer if you evaluate

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Which ordered pair is in the solution set of the system of linear inequalities? y >3/2 x – 1 y < 3/2x – 1

OLEGan [10]

Answer:

The correct option is 4.

Step-by-step explanation:

The given inequalities are

$y>\frac{3}{2}-1$ .... (1)

$y$ .... (2)

From the given inequalities it is noticed that the related equation of both inequalities is

$y=\frac{3}{2}-1$

This line is dotted line because the sign of inequality is ">" and "<".

The shaded region of first inequality is upper side of the related line. The shaded region of second inequality is lower side of the related line.

Since there is no common shaded region, therefore the system of inequalities has no solution and option 4 is correct.

7 0

3 years ago

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Which of these expression is equivalent to -2(3-y)

Alisiya [41]

A. -6+2y

Step-by-step explanation:

-2×3-2×(-y)

multiply the numbers

-6-2×(-y)

multiplying two negatives equals a positive

-6+2y

8 0

3 years ago

Read 2 more answers

The equations that must be solved for maximum or minimum values of a differentiable function w=f(x,y,z) subject to two constrai

sammy [17]

The Lagrangian is

$L(x,y,z,\lambda,\mu)=x^2+y^2+z^2+\lambda(4x^2+4y^2-z^2)+\mu(2x+4z-2)$

with partial derivatives (set equal to 0)

$L_x=2x+8\lambda x+2\mu=0\implies x(1+4\lambda)+\mu=0$

$L_y=2y+8\lambda y=0\implies y(1+4\lambda)=0$

$L_z=2z-2\lambda z+4\mu=0\implies z(1-\lambda)+2\mu=0$

$L_\lambda=4x^2+4y^2-z^2=0$

$L_\mu=2x+4z-2=0\implies x+2z=1$

Case 1: If $y=0$ , then

$4x^2-z^2=0\implies4x^2=z^2\implies2|x|=|z|$

Then

$x+2z=1\implies x=1-2z\implies2|1-2z|=|z|\implies z=\dfrac25\text{ or }z=\dfrac23$

$\implies x=\dfrac15\text{ or }x=-\dfrac13$

So we have two critical points, $\left(\dfrac15,0,\dfrac25\right)$ and $\left(-\dfrac13,0,\dfrac23\right)$

Case 2: If $\lambda=-\dfrac14$ , then in the first equation we get

$x(1+4\lambda)+\mu=\mu=0$

and from the third equation,

$z(1-\lambda)+2\mu=\dfrac54z=0\implies z=0$

Then

$x+2z=1\implies x=1$

$4x^2+4y^2-z^2=0\implies1+y^2=0$

but there are no real solutions for $y$ , so this case yields no additional critical points.

So at the two critical points we've found, we get extreme values of

$f\left(\dfrac15,0,\dfrac25\right)=\dfrac15$ (min)

and

$f\left(-\dfrac13,0,\dfrac23\right)=\dfrac59$ (max)

5 0

4 years ago

Consider the circle graph below of the type of flowers planted in a garden. If 72 tulips are in the garden, how many sunflowers

blagie [28]

Answer:

44

Step-by-step explanation:

The answer is 44 or d because 18% is equal to 72 so that means 9% = 36 then you just you round

8 0

4 years ago

Please help me it would mean a lot thank you:)

Alexeev081 [22]

Number 4. will be a. because if you do 7*9=63*10=630.

5 0

4 years ago

Read 2 more answers