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Rom4ik [11]
3 years ago
7

A rectangular safe can hold 5,184 cubic inches. Gold bars that are 3 inches by 6 inches by 2 inches fit to completely fill the s

afe. What is the volume of each gold bar?
Mathematics
2 answers:
Marrrta [24]3 years ago
6 0

Answer: The volume of each gold bar is 36 in³.

Step-by-step explanation:

Since we have given that

Length of gold bar = 3 inches

Breadth of gold bar = 6 inches

Height of gold bar = 2 inches

So, Volume of each gold bar would be

Length × breadth × height

3\times 6\times 2\\\\=36\ in^3

Hence, the volume of each gold bar is 36 in³.

Len [333]3 years ago
5 0
V = l x w h = 3 x 6 x 2 = 36
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0.5,1:5,0.35,12/25,4/5 in least to greatest
Andre45 [30]


First we must convert all the values to one mathematical state. We shall convert each to its decimal figure.

a) 0.5 is already a decimal so we leave it alone

b) 1: 5 when simplified makes  1/6  = 0.16

c) 0.35 is already a decimal so we will not touch it.

d) 12/25  = 0.48

e) 4/5 = 0.8

so now we arrange these from the least to greatest:

b, c, a, d, e,

 now we equate this with the original values so the answer will be:

1:5,  0.35,  0.5,  12/25,  4/5 

3 0
3 years ago
PLEASE SHOW YOUR WORK!!! WILL MARK BRAINLIEST!!!
Anna11 [10]

Answer:

45

Step-by-step explanation:

3 out of 12 is 1/4, or 0.25, so if you divide 180 by 4, then using the same logic, you can expect 45 kids to have played last year.

3 = 1/4 OR .25 of 12, 12 divided by 4 = 3

180 divided by 4 = 45

4 0
3 years ago
Read 2 more answers
3. Bobbi bought 4 rolls of
sveta [45]

Answer:

400 x however long those ribbons are

Step-by-step explanation:

1 meter is 100 centimeters, and there are four rolls. so 4x100 equals 400, and you multiply that by the length that you didn't provide.

3 0
2 years ago
You have two pieces of string. One is 8 cm long. The other is 20 centimeters long. You want to cut each piece if string into sma
Minchanka [31]

ah, basically what length can you divide each string to get a certain length

factor each

8=2*2*2

therefor:

8=1*8=2*4=4*2=8*1

so you can have 1 length of string 8cm long

2 lengths of string 4cm long

4 lengths of string 2cm long

8 lengths of string 1cm long


20cm string

factor

20=1*2*2*5

so 20=1*20=2*10=4*5=5*4=10*2=20*1

you can have 1 string 20cm long

2 strings 10cm long

4 strings 5cm long

5 strings 4cm long

10 strings 2cm long

20 strings 1cm long


we need greatest common length


in 8cm stirng, we have 1,2,4,8

in 20cm string, we have 1,2,4,5,10,20

greatest common length is 4


answer is 4cm


alternately, you could have done this:

8=2*2*2

20=2*2*5

common grooup is 2*2=4 so 4 is answer

6 0
3 years ago
Mr. Rich had 2 times more cars than motorcycles in his garage. After he bought 1 more car and sold 2 motorcycles, there were 3 t
Degger [83]

Answer:

After the sale there were 15 cars and 5 motorcycles

Step-by-step explanation:

c=cars originally

m=motorcycles originally

c=2m  (2 times the cars than motorcycles)

(c+1)  bought 1 car  after sale

sold 1 motor cycle (m-2)  after sale

(c+1) = 3(m-2)   (3 times more cars than motorcycles)


(c+1) = 3(m-2)

distribute

c+1 = 3m-6

substitute c =2m

2m +1 = 3m-6

subtract 2m from each side

2m+1-2m = 3m-6-2m

1 = m-6

add 6 to each side

1+6 = m-6+6

m=7

c = 2m

c = 2(7) =14

c=14

Originally there were 7 motorcycles and 14 cars

After the sale c+1 = 15, m-2 = 5

there were 15 cars and 5 motorcycles

7 0
3 years ago
Read 2 more answers
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