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3 years ago

Helppppppppppppppppppppppppppp

Mathematics

1 answer:

Paul [167]3 years ago

6 0

Answer:

20, and 26 are the middle - 23 is the average. Your answer is 23.

Step-by-step explanation:

So since they are in order from least to greatest, basically it's the middle one.

Since there is an even number and there isn't a middle one (like it is here) then, it is the average of the middle two.

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40 POINTS PLEASE HELP AND HURRY

pentagon [3]

Answer:

The histogram that represents the correct frequency of each class interval in the given data set, is: histogram B.

What is a Histogram?

A histogram is a type of bar graph that uses bins to represent the frequency of a class interval.

Given the data points above, the histogram in option B has the correct bars that represent the appropriate frequency of each class interval.

Therefore, the histogram that represents the data set given is Histogram B.

Learn more about histograms on:

brainly.com/question/18198700

Please Do this:

<h2><u><em>Please give me brainleist!</em></u></h2>

3 0

2 years ago

Could u pls show me step by step

Brums [2.3K]

Answer:

Area = 36 sq. units

Step-by-step explanation:

The 3 values you need to solve for the area are the top base length, bottom base length, and height.

Top base length = 7 . It's the distance between point A and B.

Bottom base length = 11. It's the distance between points C and D.

Height = 4. It's the perpendicular distance from the top to the bottom base.

The formula to solve the area of a trapezoid (or trapezium, I'm American) is:

A = $\frac{1}{2}h(b_{1} +b_{2})$

Put in the numbers above for the unknowns and you will get this:

A = $\frac{1}{2}(4)(7 + 11)$

Simplify:

A= $\frac{1}{2}(4)(18)$

A = 2(18)

A = 36

So the answer is 36. Hope I helped!

5 0

4 years ago

Read 2 more answers

How to solve this :') please help

blsea [12.9K]

Answer:

3/2

Step-by-step explanation:

sin(3π/4 - β) = sin(3π/4)cosβ - cos(3π/4)sinπ =

$\sin(\frac{3\pi}{4}-\beta)=\sin(\frac{3\pi}{4})\cos\beta-\cos\frac{3\pi}{4}\sin\beta\\=\frac{1}{\sqrt{2}}\cos\beta-(-\frac{1}{\sqrt{2}})\sin\beta\\\\=\frac{1}{\sqrt{2}}(\cos\beta +\sin\beta)\\\\\sin^2(\frac{3\pi}{4}-\beta)=\frac{1}{2}\cos\beta +\sin\beta)^2=\frac{1}{2}(\cos^2\beta +\sin^2\beta+2\sin\beta\cos\beta\\=\frac{1}{2}(1+\sin2\beta)=\frac{1}{2}(1-\frac{1}{5}) = \frac{2}{5}\\$