Section 1:
using this format we can determine what the answer is:
42 105
—— • ——-
100 x
(the spacing may be off but imagine two separate fractions)
first multiply 100 by 105 to get 10,500
then divide by 42 to get 250
this means that sasha’s book has 250 pages
section b:
using the same formula we can solve this problem:
first we need to multiply 250 by 2 to get the total cost of both tickets
175 x
—— • ——
100 500
(again spacing may be off but think of two separate fractions)
then multiply 500 by 175 to get 87,500
then divide by 100 to get 875
to find the profit subtract 875-500
this means he will make $375 profit
conclusion:
sasha’s book has 250 pages
trevor will make $375 profit
this is the method my teacher taught me last year so it should be right, hope this helps and please mark brainliest!!
Answer:
22 feet in centimeters is 670.56
22 inch in centimeters is 55.88
Step-by-step explanation:
Answer:
pretty sure it is 1.8478125
Step-by-step explanation:
We are given with three equations and three unknowns and we need to solve this problem. The solution is shown below:
Three equations are below:
3x + 4y - z = -6
5x + 8y + 2z = 2
-x + y + z = 0
use the first (multiply by +2) and use the second equation:
2 (3x+4y -z = -6) => 6x + 8y -2z = -12
+ ( 5x + 8y +2z = 2)
------------------------
11x + 16y = -10 -> this the fourth equation
use the first and third equation:
3x + 4y -z = -6
+ (-x + y + z =0)
-------------------------
2x + 5y = -6 -> this is the fifth equaiton
use fourth (multiply by 2) and use fifth (multiply by -11) equations such as:
2 (11x + 16y = -10) => 22x + 32y = -20 -> this is the sixth equation
-11 (2x + 5y = -6) => -22x -55y = 46 -> this is the seventh equation
add 6th and 7th equation such as:
22x + 32y = -20
+(-22x - 55y = 66)
---------------------------
- 23y = 46
<span> y = -2
solving for x, we have:
</span>2x + 5y = -6
2x = -6 - 5y
2x = -6 - (5*(-2))
2x = -6 +10
2x = 4
x=2
solving for y value, we have:
-x + y + z =0
z = x -y
z = 2- (-2)
z =4
The answers are the following:
x = 2
y = -2
z = 4
A. ∠ACE ≅ ∠ACE
This is correct.
