3 years ago

Factor the question completely

Mathematics

1 answer:

Stella [2.4K]3 years ago

7 0

Answer: (2b+7)(5a-3)

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Simplify x+2/x^2+2x-3 divide by x+2/x^2-x

ira [324]

$\dfrac{\frac{x+2}{x^2+2x-3}}{\frac{x+2}{x^2-x}}$

If $x\neq-2$ , then we can immediately cancel the factors of $x+2$ :

$\dfrac{\frac1{x^2+2x-3}}{\frac1{x^2-x}}=\dfrac{x^2-x}{x^2+2x-3}$

Factorize the numerator and denominator:

$x^2-x=x(x-1)$

$x^2+2x-3=(x+3)(x-1)$

Next, if $x\neq1$ , then

$\dfrac{x^2-x}{x^2+2x-3}=\dfrac{x(x-1)}{(x+3)(x-1)}=\dfrac x{x+3}$

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3 years ago

5.03+13.7+108 what is the answer an how do u solve it

jarptica [38.1K]

Answer:

126.73

Step-by-step explanation:

5.03+13.7+108

5.03+13.7= 18.73

18.73 +108=

126.73

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3 years ago

Choose all the fractions that are equivalent to1/7. (Click all that apply.)

Alchen [17]

Answer:

2/14, 4/28, 5/35, 7/70 or just 2/14

Step-by-step explanation:

Multiply both the numerator and denominator of 1/7 by 2, to get 2/14, or 2:14

And multiply the numerator and denominator of 1/7 by 3, to get 3/21, or 3:21. So 2:14 and 3:21 are two ratios that are equal to 1:7.

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3 years ago

At the market, 8 apples cost $4, 4. How much do 9 apples cost?

ella [17]

Answer: i need more information 8 apples cost $4, 4???????

Step-by-step explanation:

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3 years ago

In which data set is the mean equal to the median?

sdas [7]

Answer:

The number in the middle

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2 years ago