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maks197457 [2]
4 years ago
14

Factor the question completely

Mathematics
1 answer:
Stella [2.4K]4 years ago
7 0
Answer: (2b+7)(5a-3)
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Solve x^3 = 125<br><br> A) x = 5 <br><br> B) x = 25 <br><br> C) x = 5 √5<br><br> D) x = 1,953,125
stellarik [79]
The answer is A. <span>x = 5 because if you multiply 5 by itself 3 times i equals to 125.

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The pitch of a roof is indicated by a fraction formed by placing the rise over the
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julia-pushkina [17]
V =  \frac{1}{3}  \pi r^2h \ \ \ \ \text{[r=radius, h=height ]} \\ \\ V =  \frac{1}{3}*(5)^2*11 *  \pi  = \frac{1}{3}*25*11 *  \pi  = \frac{275}{3} \pi =91 \frac{2}{3} \pi   \ units^3

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The distance between San Antonio and Austin is 6 inches on the map. If the scale on the map is 1.5 inches is equal to 35 miles.
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MATRECIES: Suppose ={u,v,w}⊆R3 is linearly independent. Determine if the set 4 ={u, v, v−w, u+v+w} is linearly independent or li
AlladinOne [14]

The set is linearly dependent.

To explicitly prove this, we need to show there is at least one choice of constants c_1,c_2,c_3,c_3\in\Bbb R such that

c_1 u + c_2 v + c_3(v-w) + c_4(u+v+w) = 0

or equivalently,

(c_1 + c_4) u + (c_2 + c_3 + c_4) v + (-c_3 + c_4) w = 0

which is the same as solving the system of equations

\begin{cases} c_1 + c_4 = 0 \\ c_2 + c_3 + c_4 = 0 \\ -c_3 + c_4 = 0 \end{cases}

From the first and last equations, we have c_1=-c_4 and c_3=c_4. Substituting these into the second equation leaves us with c_2-2c_1=0, and so the overall solution set is

c_1 = \dfrac12 c_2 = -c_3 = -c_4

for which there are infinitely many not-all-zero solutions.

3 0
1 year ago
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