Answer:
I found two different solutions. Hope one of them help!
1. x = -1/3 = -0.333
2. x = 5/2 = 2.500
Step-by-step explanation:
13 ± √ 289
x = ——————
12
Can √ 289 be simplified ?
Yes! The prime factorization of 289 is
17•17
To be able to remove something from under the radical, there have to be 2 instances of it (because we are taking a square i.e. second root).
√ 289 = √ 17•17 =
± 17 • √ 1 =
± 17
So now we are looking at:
x = ( 13 ± 17) / 12
Two real solutions:
x =(13+√289)/12=(13+17)/12= 2.500
or
x =(13-√289)/12=(13-17)/12= -0.333
Two solutions were found :
x = -1/3 = -0.333
x = 5/2 = 2.500
Answer:
-6.2
Step-by-step explanation:
just because.
a.
The polynomial w^2+18w+84 cannot be factored
The perfect square trinomial is w^2+18w + 81
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The reason the original can't be factored is that solving w^2+18w+84=0 leads to no real solutions. Use the quadratic formula to see this. The graph of y = x^2+18x+84 shows there are no x intercepts. A solution and an x intercept are basically the same. The x intercept visually represents the solution.
w^2+18w+81 factors to (w+9)^2 which is the same as (w+9)(w+9). We can note that w^2+18w+81 is in the form a^2+2ab+b^2 with a = w and b = 9
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b.
The polynomial y^2-10y+23 cannot be factored
The perfect square trinomial is y^2-10y + 25
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Using the quadratic formula, y^2-10y+23 = 0 has no rational solutions. The two irrational solutions mean that we can't factor over the rationals. Put another way, there are no two whole numbers such that they multiply to 23 and add to -10 at the same time.
If we want to complete the square for y^2-10y, we take half of the -10 to get -5, then square this to get 25. Therefore, y^2-10y+25 is a perfect square and it factors to (y-5)^2 or (y-5)(y-5)
D.) "The graphs of the equations intersect each other at two places."
Answer:
(1, No, No) (2, No, Yes) (3, 6x^2+10) (4, 2x^2-3) (5, x^2-x) (6, -2x^4+12x+3)
(7, 3x^3+15x^2+20) (8, 9x^3 + 4x^2+8x) (9, xy+2x+6y+5) Sorry didn't have an answer for 10. I hope they are all correct sorry for the wait.
Step-by-step explanation:
