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gtnhenbr [62]
3 years ago
14

if 24000 bricks of the same shape and size are required to build a wall of dimensions 15m*6m*20cm ,find the volume of each brick

s​
Mathematics
1 answer:
zepelin [54]3 years ago
7 0

1800m cube to the power of 3 ans

may be this helpful!

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Please help me me with this please actually help me please and thank you
Vsevolod [243]

Answer:

A. (-1, 3)

Step-by-step explanation:

To solve, find which point in the options are in the double shaded region (the region that is shaded the darkest which is the region above the point where the lines cross).

A. (-1, 3) is the correct answer because it falls in the correct region.

B. (-4, 1) is not the correct answer because it does not fall ABOVE both lines like the question says.

C. (0, 1) is not the correct answer because it falls in the 2nd darkest region.

6 0
2 years ago
What would justify these triangles????
olganol [36]

Answer:

ASA would justify it to be congruent.

5 0
3 years ago
The height of an ostrich is 20 inches more than 4 times the height of a kiwi. If an ostrich is 108 inches tall, how tall is a ki
blagie [28]
The answer would be (108-20)4=22
3 0
3 years ago
Read 2 more answers
Answer choices:
vova2212 [387]
A and T are points. On their own, they cannot define a line. So we can rule out choice A

WCR and TRA are angles. For any triple the points do not fall on the same straight line. So we cannot define any lines here. This crosses off choice B

Choice C is the answer because WC does define a line. We only need two points to form a line. Similarly CR does the same job. We draw a line marker with two arrows at each end to be placed over the letters to indicate "line". 

Choice D is similar to choice D; however, it is not the answer because WT is the same line as WC. In other words, WC = WT. We haven't named a new line at all. We're simply repeating ourselves. 
6 0
3 years ago
D= kA [T2 - T1 / L] Solve for T1
mel-nik [20]
d=\dfrac{k_A(T_2-T_1)}{T}\ \ \ \ |multiply\ both\ sides\ by\ T\\\\k_A(T_2-T_1)=dT\ \ \ \ |divide\ both\ sides\ by\ k_A\\\\T_2-T_1=\dfrac{dT}{k_A}\ \ \ \ |subtract\ T_2\ from\ both\ sides\\\\-T_1=\dfrac{dT}{k_A}-T_2\ \ \ \ \ |change\ signs\\\\\boxed{T_1=T_2-\frac{dT}{k_A}}
5 0
3 years ago
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