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saveliy_v [14]
3 years ago
7

Which statement correctly identifies a local minimum of the graphed function?

Mathematics
2 answers:
4vir4ik [10]3 years ago
4 0

That would be option C.

Rina8888 [55]3 years ago
3 0

Answer:

C. Over the interval [–1, 0.5], the local minimum is 1.

Step-by-step explanation:

From the graph we observe the following:

1) x intercepts are two points.

ii) y intercept = 1

f(x) = y increases from x=-infinity to -1.3

y decreases from x=-1.3 to 0

Again y increases from x=0 to end of graph.

Hence in the interval for x as (-1.3, 1) f(x) has a minimum value of (0,1)

i.e. there is a minimum value of 1 when x =0

Since [-1,0.5] interval contains the minimum value 1 we find that

Option C is right answer.

There is a local minimum of 1 in the interval [-1,0.5]



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Answer:

1, 2, 3

Step-by-step explanation:

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The first option is -100. That's less than 20, so this statement is true.

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3 years ago
Carter is solving for x by the process of completing the square for the following
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The number that goes in place of the question mark is 2.

Step-by-step explanation:

Let's solve it!

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Now we'll add 12 to both sides to complete the square:

x² + 4x + 4 = 12

And finish it off:

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So the answer to the question is 2

Bonus:

We can also now solve this for x:

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It is given that y varies inversely as x^2. If x is decreased by 50%, find the percentage change in y.
vova2212 [387]

Answer:

300%

Step-by-step explanation:

Given

y\ \alpha\ \frac{1}{x^2}

Required

Find the percentage change in y when x decreased by 50%

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When x decreased by 50%

Y = \frac{k}{(x - 0.5x)^2}

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Expand

Y = \frac{1}{0.25} * \frac{k}{x^2}

Substitute \frac{k}{x^2} for y

Y = \frac{1}{0.25} * y

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The percentage change is then calculated as:

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<em>The percentage in y is 300%</em>

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3 years ago
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Answer:

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