Answer:
y = x - 2
Step-by-step explanation:
Parallel lines have the same slope, so the line will also have a slope of 1.
Plug in the slope and given point into y = mx + b to solve for b:
y = mx + b
-1 = 1(1) + b
-1 = 1 + b
-2 = b
Plug in b and the slope into y = mx + b
y = x - 2 is the equation
Answer:
Explain the question a little better
Step-by-step explanation:
It is hard to understand ur question. Please restate it in a better way.
Answer:


Step-by-step explanation:
Given
See attachment for MNPQ and RSTU
Required
Find x and y
To solve this question, we make use of equivalent ratios of corresponding side lengths.
The ratio of corresponding sides are:




From the attachment, we have:



To solve for x, we equate
and 

Express as fraction

Make x the subject




To solve for y, we equate
and 

Express as fraction

Make y the subject




Answer:The greatest common factor is 15 to 10.
Step-by-step explanation:
Answer:
The areas are equal.
Step-by-step explanation:
Let the first rectangle be R and
the second rectangle be R'.
Sine R and R' are identical, their lengths are equal and their breadths are equal.
So, if Inga divided each into equal parts, then each part of both rectangles are equal.
Hence, the colored parts of both rectangles are equal.