Plugging -6 in for x, we get -2sqrt(-6-7+1)=sqrt(something negative) which is clearly not possible.
Plugging -6 in for f(x), we get -6=-2sqrt(x-7+1) and 3=sqrt(x-7+1). Squaring both sides, we get 9=x-7+1 and by adding both sides by 6 we get 15=x, therefore having (15,-6) and proving that -6 is in the range, but not the domain (B)
I think true because the X increases