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Norma-Jean [14]
3 years ago
12

Sixteen college freshmen were asked to record the number of books they typically read in a week. here are their data: 2, 4, 6, 0

, 1, 10, 9, 0, 6, 3, 6, 8, 5, 4, 6, 2. what is the range of this distribution?
Mathematics
1 answer:
madam [21]3 years ago
8 0
I believe you just add all the numbers then divide by how many were there. You would divide by 16.
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10% of what number is 300?
sergij07 [2.7K]

10% of what number is 300?

This means that the number is greater than 300 and in fact 10 times greater. You can create and equation. Let x be the number.

0.1x=300

x=3000

answer:3000

8 0
2 years ago
Danella makes $13 an hour. If she makes time and half in overtime, what is her overtime rate?
dlinn [17]

Answer:

Her overtime rate would be $19.5.

Step-by-step explanation:

Half of 13 is 6.5. If you add that to the $13 she makes, it would be $19.5.

8 0
2 years ago
Write an algebraic expression for the perimeter of a rectangular garden with a width of 3 metres and a length of 2y metres. Simp
anyanavicka [17]

Answer:

P = 2(2y+3)

P = 30

Step-by-step explanation:

P = 2 (L+W) or P = L + L + W + W

P = 2 (2y+3)

P = 4y+6

Plug in 6 for y.

P = 24+6

P = 30

5 0
2 years ago
A quadratic function y=f(x)y=f(x) is plotted on a graph and the vertex of the resulting parabola is (5, -6)(5,−6). What is the v
MariettaO [177]

Answer:

The vertex is at (5,4).

Step-by-step explanation:

I graphed both of the functions on the graph below.

If this answer is correct, please make me Brainliest!

5 0
2 years ago
Determine
mihalych1998 [28]

Answer:

=4.+2.

Step-by-step explanation:

<u>Linear Combination Of Vectors </u>

One vector \vec b is a linear combination of \vec a_1 and \vec a_2 if there are two scalars x_1, x_2 such as

\vec b=x_1\vec a_1+x_2\vec a_2

In our case, all the vectors are given in R^3 but there are only two possible components for the linear combination. This indicates that only two conditions can be used to determine both scalars, and the other condition must be satisfied once the scalars are found.

We have

\vec a_1=,\ \vec a2=,\ \vec b=

We set the equation

=x_1.+x_2.

Multiplying both scalars by the vectors

=+

Equating each coordinate, we get

4x_1-4x_2=8

5x_1+3x_2=26

-4x_1+3x_2=-10

Adding the first and the third equations:

-x_2=-2

x_2=2

Replacing in the first equation

4x_1-4(2)=8

4x_1=8+8

x_1=4

We must test if those values make the second equation become an identity

5(4)+3(2)=20+6=26

The second equation complies with the values of x_1 and x_2, so the solution is

=4.+2.

8 0
3 years ago
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