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notka56 [123]
3 years ago
7

9 x {[14/2+(4-1)]-8}

Mathematics
1 answer:
valentina_108 [34]3 years ago
6 0

Answer:

36

Step-by-step explanation:

order of operations

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Gina's number is 2 more than sara's. the sum of their numbers is 68. what are their numbers?
ikadub [295]

In order to solve this problem, we transform the statements into algebraic expressions. First, we assign the variables.

 

Let:

x = Gina’s number

y = Sara’s number

 

For the first equation, we show that Gina’s number is greater than Sara’s number by 2. For the second equation, we show that the sum of both numbers is 68.

<span>(1)  </span>x – y = 2

<span>(2)  </span>x + y = 68

 

<span>We add the two expressions, which result in the expression: 2x = 70. Then we divide 70 by 2 to get the value of x. We then have x = 35. Using the second equation, we solve for y = 68-35. This gives y = 33. To summarize, Gina’s number is 35 while Sara’s number is 33.</span>
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Ways to solve a division problem
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Long division, calculator, mental math'

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Find the Jacobian ∂(x, y, z) ∂(u, v, w) for the indicated change of variables. If x = f(u, v, w), y = g(u, v, w), and z = h(u, v
jeyben [28]

Answer:

The Jacobian ∂(x, y, z) ∂(u, v, w) for the indicated change of variables

= -3072uv

Step-by-step explanation:

<u>Step :-(i)</u>

Given  x = 1 6 (u + v)  …(i)

  Differentiating equation (i) partially with respective to 'u'

               \frac{∂x}{∂u} = 16(1)+16(0)=16

  Differentiating equation (i) partially with respective to 'v'

              \frac{∂x}{∂v} = 16(0)+16(1)=16

  Differentiating equation (i)  partially with respective to 'w'

               \frac{∂x}{∂w} = 0

Given  y = 1 6 (u − v) …(ii)

  Differentiating equation (ii) partially with respective to 'u'

               \frac{∂y}{∂u} = 16(1) - 16(0)=16

 Differentiating equation (ii) partially with respective to 'v'

               \frac{∂y}{∂v} = 16(0) - 16(1)= - 16

Differentiating equation (ii)  partially with respective to 'w'

               \frac{∂y}{∂w} = 0

Given   z = 6uvw   ..(iii)

Differentiating equation (iii) partially with respective to 'u'

               \frac{∂z}{∂u} = 6vw

Differentiating equation (iii) partially with respective to 'v'

               \frac{∂z}{∂v} =6 u (1)w=6uw

Differentiating equation (iii) partially with respective to 'w'

               \frac{∂z}{∂w} =6 uv(1)=6uv

<u>Step :-(ii)</u>

The Jacobian ∂(x, y, z)/ ∂(u, v, w) =

                                                         \left|\begin{array}{ccc}16&16&0\\16&-16&0\\6vw&6uw&6uv\end{array}\right|

   Determinant       16(-16×6uv-0)-16(16×6uv)+0(0) = - 1536uv-1536uv

                                                                                 = -3072uv

<u>Final answer</u>:-

The Jacobian ∂(x, y, z)/ ∂(u, v, w) = -3072uv

 

               

     

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Step-by-step explanation        :

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Answer:

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Step-by-step explanation:

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